All categories

3 years ago

Question 1 (1 point)

Mathematics

2 answers:

Phantasy [73]3 years ago

8 0

Answer:

The correct answer is A) 166x

Hoped I helped

Amanda [17]3 years ago

3 0

Answer:

a) 166x.

Step-by-step explanation:

167x - x

= 166x.

You might be interested in

Find the measures of two angles, one positive and one negative that are coterminal with pi/5

lozanna [386]

To find coterminal angles for an angle, β, given in radians use the following formula:
coterminal angle = β + 2πk
where k is an integer {..., -3, -2, -1, 0, 1, 2, 3, ...}
Negative Coterminal Angle: k = -1
NCA = π/5 + 2π(-1)
= -9π/5
Positive Coterminal Angle: k = 1
PCA = π/5 + 2π(1)
= 11π/5
The following answers are just one of many possible answer... you have infinite number of choices for k.
$NCA = \frac{-9 \pi }{5}$
$PCA= \frac{11 \pi }{5}$

7 0

3 years ago

For what value(s) of k will the relation not be a function

skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

$R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]$

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$k-8.3+2.4k=-\frac{3}{4} k$

$3.4k-8.3=-\frac{3}{4}k$

$3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10$

$4k-83=-\frac{15}{2}k$

$34k=-\frac{15}{2}k+83$

$\frac{83}{2}k=83$

$83k=166$

$k=2$ ............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$2-|k+1|=-6$

$2-\left|k+1\right|-2=-6-2$

$-\left|k+1\right|=-8$

$\left|k+1\right|=8$

Since, this is absolute function

so, we can break it into two parts

$|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a$

$k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8$

we get

$k+1=-8\quad$

$k=-9$

$k+1=8\quad$

$k=7$

so,

$k=-9\quad \mathrm{or}\quad \:k=7$ ...............Answer

5 0

3 years ago

Please helppp!!<br> For the equation y = 3x – 6 Complete the table for the x values given.

enot [183]

Answer:

Step-by-step explanation:

y = 3x -6

x = -2, y = -12

x = -1, y = -9

x = 0, y = -6

x = 1, y = -3

x = 2, y = 0

x= 3, y = 3

x -2 -1 0 1 2 3

y -12 -9 -6 -3 0 3

6 0

3 years ago

$350 in the ratio 4:3

kherson [118]

Answer:

$200 : $150

Step-by-step explanation:

Sum the parts of the ratio, 4 + 3 = 7 parts

Divide the total by 7 to find the value of one part of the ratio.

$350 ÷ 7 = $50 ← value of 1 part of the ratio

4 parts = 4 × $50 = $200

3 parts = 3 × $50 = $150

8 0

2 years ago

Find the quotient of 21x^2y^6+6xy^3-30xy/3xy.

kaheart [24]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------$

$\bf \cfrac{21x^2y^6+6xy^3-30xy}{3xy}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{21x^2y^6}{3xy}+\cfrac{6xy^3}{3xy}-\cfrac{30xy}{3xy}}
\\\\\\
\cfrac{21}{3}\cdot x^2x^{-1}y^6y^{-1}+\cfrac{6}{3}\cdot x^1x^{-1}y^3y^{-1}-\cfrac{30}{3}\cdot x^1x^{-1}y^1y^{-1}
\\\\\\
7x^{2-1}y^{6-1}+2x^{1-1}y^{3-1}-10x^{1-1}y^{1-1}\implies 7xy^5+2y^2-10$

3 0

2 years ago

Read 2 more answers