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jek_recluse [69]
3 years ago
11

What should be added to 5xy to get 9xy​

Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0

Answer: 4xy

Brainliest?

larisa86 [58]3 years ago
8 0

Hello!

9xy-5xy=4xy

We can add like terms.

Like terms are same variables. Examples:

x+x

Remember:

x+x^2 can't be simplified.

y+x can't be simplified.

Hope it helps!

~Just a determined teen

#CarryOnLearning

MysteriousNature

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5(x-4)=15<br> find out what x is
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7

Step-by-step explanation:

7-4=3

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I need help with this question
Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

$ \frac{-(\sqrt{3} + 1)}{2\sqrt{2}} $

$ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $

Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

(A) $ sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4}  + \frac{\pi}{6}) $

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}

(B) Cos(A + B) = CosAcosB - SinASinB

$ cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}}) $

$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

$ \implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}) $

$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}

(C) Tan(A + B) = $ \frac{Sin(A +B)}{Cos(A + B)} $

From the above obtained values this can be calculated and the value is $ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $.

3 0
3 years ago
What is the value of 5s in 155,523,962
8_murik_8 [283]
The values would be...

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155,500,000

i hope i'm not wrong. I did the highest fives to the lowest ones.
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