Answer:
<h2>93.02 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%5C%5C)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B5.6%20%5Ctimes%20%20%7B10%7D%5E%7B25%7D%20%7D%7B6.02%20%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%3D%2093.023...)
We have the final answer as
<h3>93.02 moles</h3>
Hope this helps you
26.5 g of Fe₂(SO₄)₃
Explanation:
We have the following chemical reaction:
2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄
number of moles = mass / molecular wight
number of moles of FePO₄ = 20 / 151 = 0.1325 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃
then 0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃
X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃
mass = number of moles × molecular wight
mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g
Learn more about:
number of moles
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Answer:
1.2*10^24 molecules of CF4
Explanation:
the molar mass of cf4 is 88.0043 g/mol
176/88.0043 = 2 moles of CF4
Then multiply by avogadro's number (6.022*10^23) to get the number of molecules
2*6.022*10^23 = 1.2*10^24 molecules of CF4
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