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erik [133]
2 years ago
5

Kate wants to buy a new bicycle from a sporting goods store. The bicycle she wants normally sells for $800. The store has a sale

where all bicycles cost 7 8 of the regular price. What is the sale price of the bicycle?
Mathematics
2 answers:
klio [65]2 years ago
7 0

Answer:

700 dollars.

Step-by-step explanation:

The sale price is basically the new price of the bycicle. Therefore, is all bycicles cost 7/8 of their normal value, \frac{7}{8} (800)=700. So during this sale at the sporting goods store, the bycicle would cost 700 dollars.

lozanna [386]2 years ago
7 0

An$wer:

$700

Step-by-step explanation:

7/8 * 800 = 7/8 * 800/1

= 7 * 800/8 * 1 ( 800 and 8 are simplified to 100 and 1 )

= 7 * 100 / 1* 1

=700/1 = <u>700</u>

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option 3

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0.54

Step-by-step explanation:

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6 0
3 years ago
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If the starting time is 7:43 and the elapsed time is 36 minutes then what time what is the ending time
Annette [7]

Answer:

8:19

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6 0
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Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

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