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Marta_Voda [28]
2 years ago
13

Find the midpoint of the segment whose endpoints are (-6,-8) and (3,6) show your work!

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

Distance

=

\sqrt{(a {}^{2} -  a {}^{1}) {}^{2} +(b{}^{2} -  b {}^{1}) {}^{2}   }

=

=  \sqrt{( - 8 + 6) {}^{2}  + (6 - 3) {}^{2} }

\sqrt{4 + 9}

=  \sqrt{13}

=3.61/2

=1.8

pogonyaev2 years ago
3 0

Answer:

-1.5, -1

Step-by-step explanation:

midpoint formula

(x1 + x2 / 2) , (y1 + y2/ 2)

-6 + 3 / 2 ,   -8  + 6 / 2

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Find the sum of the 1st 100 terms: 100+98+96+......<br> 50<br> 100<br> -98<br> 1000
Mice21 [21]

<u>Answer:</u>

100

<u>Step-by-step explanation:</u>

Given :

Terms ( n ) = 100

First term ( a ) = 100

Series = > 100 + 98 + 96 .......

Common difference ( d ) = 98 - 100 = > - 2

We know sum formula:

S_n = ( n / 2 ) ( 2 a + ( n - 1 ) d )

= > S_100 = ( 100 / 2 ) ( 200 + ( 100 - 1 ) - 2 )

= > S_100 = 50 ( 200 - 198 )

= > S_100 = 50 ( 2 )

= > S_100 = 100

Therefore, sum of first 100 terms is 100.

8 0
3 years ago
Joseph has started completing the square on the equation 3x^2 - 7x + 12 = 0. He has worked to the point where he has the express
ololo11 [35]
3x^2 - 7x + 12 = 0...move the 12 to the other side
3x^2 - 7x = -12....now divide by 3
x^2 - 7/3x = -4..this is where he made his mistake
3 0
3 years ago
Vladimir buys 1.20 pounds of Skittles, 312 pounds of M&amp;Ms, and 5.2 pounds of pretzels. If the candy cost $1.20 a pound and t
musickatia [10]

Answer: 10.90

Step-by-step explanation:

5.18 for candy and 5.72 for pretzels

1.20 + 3.12 = 4.32

4.32 x 1.20 = 5.18

5.2 x 1.10 = 5.72

5.18 + 5.72 = 10.90

hope this helps

plz mark brainleist

3 0
2 years ago
A survey of 70 students from a high school is conducted. From this sample, it is found that 58 students have sent a text message
Irina-Kira [14]
Number of students who have sent a text message only is given by the difference between those that have sent a text message and those that have done both.
i.e. Number of students who has sent a text message only = 58 - 12 = 46

Number of students who have uploaded a selfie only is given by the difference between those that have uploaded a selfie and those that have done both.
i.e. Number of students who have uploaded a selfie only = 21 - 12 = 9

The total number of students surveyed is 70.
Let the number of students who have neither sent a text message nor taken a selfie today  be x, then
46 + 9 + 12 + x = 70
67 + x = 70
x = 70 - 67 = 3

Therefore, 3 students neither sent a text message nor taken a selfie today.

The number of students that have sent a text message or have taken a selfie today is given by the sum of the number of students that have sent a text message and the number of students that have taken a selfie less the number of people that have done both.
i.e. number of students that have sent a text message or have taken a selfie today = 58 + 21 - 12 = 67.
7 0
3 years ago
HELP IM BEING TIMED!!!The function f(x) is shown on the graph.
Stels [109]
All the points touch with -2,-1,1,2 and 12
8 0
3 years ago
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