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Marta_Voda [28]
2 years ago
13

Find the midpoint of the segment whose endpoints are (-6,-8) and (3,6) show your work!

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

Distance

=

\sqrt{(a {}^{2} -  a {}^{1}) {}^{2} +(b{}^{2} -  b {}^{1}) {}^{2}   }

=

=  \sqrt{( - 8 + 6) {}^{2}  + (6 - 3) {}^{2} }

\sqrt{4 + 9}

=  \sqrt{13}

=3.61/2

=1.8

pogonyaev2 years ago
3 0

Answer:

-1.5, -1

Step-by-step explanation:

midpoint formula

(x1 + x2 / 2) , (y1 + y2/ 2)

-6 + 3 / 2 ,   -8  + 6 / 2

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5. After 6 hours, the concentration is halved. After 12 hours, it will be quartered. If the original concentration is 200 nmol, a quarter is 50 nmol.

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3 years ago
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Task 1:
OleMash [197]

Answer:

maximum height is 4.058 metres

Time in air = 0.033 second

Step-by-step explanation:

Given that the equation height h

h = -212t^2 + 7t + 4

What is the toy's maximum height?

Let us assume that the equation is a perfect parabola

Time t at Maximum height will be

t = -b/2a

Where b = 7 and a = - 212

t = -7/ - 212 ×2

t = 7/ 424 = 0.0165s

Substitute t in the main equation

h = - 212(7/424)^2 + 7(7/424) + 4

h = - 0.05778 + 0.115567 + 4

h = 4.058 metres

Therefore the maximum height is 4.058 metres

How long is the toy in the air?​

The object will go up and return to the ground.

At ground level, h = 0

-212t^2 + 7t + 4 = 0

212t^2 - 7t - 4 = 0

You can factorize the above equation and pick the positive time t since time can't be negative

Or

Since we have assumed that it's a perfect parabola,

Total time in air = (-b/2a) × 2

Time in air = 0.0165 × 2 = 0.033 s

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False

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