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taurus [48]
3 years ago
12

The driving distance between London and Manchester is 195 miles. If a coach that is 50 mph leaves Manchester at 15:30pm, what ti

me will it arrive at london
Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

It will arrive at 19:24 pm at london

Step-by-step explanation:

Distance between London and Manchester = 195 miles

Speed of coach = 50 mph

Time taken to cover the given distance = \frac{Distance}{Speed}

Time taken to cover the given distance =\frac{195}{50}=3.9 hours

1 hour = 60 minutes

0.9 hours = 0.9 \times 60 = 54 minutes

So,Time taken to cover the given distance = 3 hours 54 minutes

He left at 15:30 pm

Total time taken =  3 hours 54 minutes

It will arrive at time =19:24 pm

Hence it will arrive at 19:24 pm at London

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KatRina [158]
Hello!

For this you can plug in the x values in the choices and see if you get the y value

y = -4^{3}  - (-4)

-4^3 is -64

when you subtract a negative you are just adding

-64 + 4 = 60

Then you do the second one

y =  -3^{3}  - (-3)

-3^3 is -27

-27 + 3 is -24

Then the third one

y =  -2^{3}  - (-2)

-2^3 is -8

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Then the last one

y =  -1^{3}  - (-1)

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7 0
3 years ago
If a certain cannon is fired from a height of 8.8 meters above the​ ground, at a certain​ angle, the height of the cannonball ab
Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

h(t)=-4.9t^2+30.5t+8.8

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

-49t^2+305t+88=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

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t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0
3 years ago
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Step-by-step explanation:

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