Factor by grouping: 2v^3 + 3v^2 + 4v + 6
1 answer:
<span>2v^3 + 3v^2 + 4v + 6
= (</span><span>2v^3 + 3v^2) + (4v + 6)
= v^2 (2v + 3) + 2 (2v + 3)
= (v^2 + 2)(2v + 3)
hope it helps</span>
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