4 years ago

Factor by grouping: 2v^3 + 3v^2 + 4v + 6

1 answer:

3 0

2v^3 + 3v^2 + 4v + 6
= (2v^3 + 3v^2) + (4v + 6)
= v^2 (2v + 3) + 2 (2v + 3)
= (v^2 + 2)(2v + 3)

hope it helps

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