Supplementary angles by definition means the sum is 180.
From that knowledge we can write up some equations.
Let angle 1 = x, and angle 2 = y
x + y = 180
"The larger of two supplementary angles measures 20° less than four times the measure of the smaller angle"
(Let x be the larger angle)
x+20 = 4y
Since there are two different equations, and two variables, this means we have a set of simultaneous equations.
We can solve this via the substitution method or the elimination method.
I choose to solve it via the substitution method cause of personal preference.
x + y = 180 => x = 180- y
x+20 = 4y => x = 4y - 20
Make them equal each other..
180 - y = 4y - 20
200 = 5y
40 = y
Now that we know y we can sub it into any equation to find x
x + 20 = 4y
x + 20 = 4(40)
x + 20 = 160
x = 140
So the angles are 40° and 140°
Complete question is;
Given n objects are arranged in a row. A subset of these objects is called unfriendly, if no two of its elements are consecutive. Show that the number of unfriendly subsets of a k-element set is ( n−k+1 )
( k )
Answer:
I've been able to prove that the number of unfriendly subsets of a k-element set is;
( n−k+1 )
( k )
Step-by-step explanation:
I've attached the proof that the number of unfriendly subsets of a k-element set is;
( n−k+1 )
( k )
Answer:
As a fraction, A is 3/8 concentrate in final product and B is 4/11.
A is, in other words, 33/88, and B is 36/88 concentrate in the final mixture.
So Mixture B is stronger, slightly.
Note that in order to make the fractions the same denominator, we had to 'expand' each fraction with the denominator of the other fraction. After that, the numbers are really easy to compare.
Answer:
evrone keeps asking me to find their x and then I have no time to find 'MY'X
CRIES
