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Umnica [9.8K]
3 years ago
15

Seven is reading a book while on vacation. So far, he has read 1/6 of the book. He wants to finish 3/6 of the book by the end of

vacation
Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

3/6-1/6

2/6(simplify) =1/3

SOVA2 [1]3 years ago
4 0

Answer:

She has to read 2/6 more by the end of her vacation if she wants to finish 3/6 (1/2) of the book.

Step-by-step explanation:

If this wasn't the answer you were looking for please tell me so I can redo it.

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4 years ago
Find the nth term of 6,8,10,12
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Answer:

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3 years ago
Surface integrals using a parametric description. evaluate the surface integral \int \int_{s} f(x,y,z)dS using a parametric desc
DiKsa [7]

You can parameterize S using spherical coordinates by

\vec s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\frac\pi2.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial\vec v}\times\dfrac{\partial\vec s}{\partial\vec u}=36\langle\cos u\sin^2v,\sin u\sin^2v,\cos v\sin v\rangle

(I use \vec s_v\times\vec s_u to avoid negative signs. The orientation of the normal vector doesn't matter for a scalar surface integral; you could just as easily use \vec s_u\times\vec s_v=-(\vec s_v\times\vec s_u).)

Then

f(x,y,z)=f(6\cos u\sin v,6\sin u\sin v,6\cos v)=36\sin^2v

and the integral of f over S is

\displaystyle\iint_Sf(x,y,z)\,\mathrm dS=\int_0^{\pi/2}\int_0^{2\pi}36\sin^2v\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{\pi/2}\int_0^{2\pi}(36\sin^2v)(36\sin v)\,\mathrm du\,\mathrm dv

=\displaystyle2592\pi\int_0^{\pi/2}\sin^3v\,\mathrm dv=\boxed{1728\pi}

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ASHA 777 [7]

Answer:

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Step-by-step explanation:

8 0
4 years ago
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