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malfutka [58]
3 years ago
14

The retention of five digits on the hands and feet of primates is ____. a variable trait in the order characteristic only of mon

keys characteristic only of apes and humans the only truly distinctive primate trait none of these'
Biology
1 answer:
ElenaW [278]3 years ago
7 0

The answer is ‘the only truly distinctive primate trait’. Prehensile hands are a distinctive trait of primates an opposable thumb (capable of grasping). The digits have  nails instead of claws, and tactile pads enriched with sensory nerve fibers at the ends of digits to feel to manipulate objects.






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What happens when someone eats sodium metal​
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Explanation: As soon as sodium touches your tongue, hydrogen is released with tremendous heat. Most likely an explosion will take place in your mouth. So maybe it won't be a good idea to try it unless thats what you want

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Equation of photosynthesis is .......​
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6CO2 + 6H2O -> C6H12O6 + 6O2

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A rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black,
m_a_m_a [10]

Answer:

Alleles for feather colour exhibit incomplete dominance or co-dominance.

50% gray offspring + 50% black offspring

Explanation:

<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>

Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.

Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.

15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.

Bb   x   Bb = 1BB, 2Bb, and 1bb

Crossing the gray rooster (Bb) with a black hen (bb):

Bb   x   bb = Bb, Bb, bb, and bb

          = 2Bb (gray):2bb (black)

50% of the offspring will be gray while the remaining 50% will be black.

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Hey ! The number of atoms in the reactants must be equal to the number of atoms in the products so

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Answer: The probability is 100%.

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In the question, the woman is color-blind, which means she carries the recessive alleles: X^{d}X^{d}

The man, on the other hand, is normal, so his X-linked genotype will be: X^{D}Y.

Now, since they have a daughter, she inherited her double X from each of her parents, which means she inherited one X^{d} from her mother and one X^{D} from her father.

So, the daughter's genotype can only be heterozygotic  X^{D}X^{d} in other words, the probability is 100%.

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