Answer:
<h3>6</h3>
Step-by-step explanation:
Given the expression sin(9z − 1) = cos(6z + 1), for 0 < z ≤ 90, we are to find z
Note that sin theta = cos(90-thetsa)
sin(9z − 1) = cos(6z + 1)
cos (90 - (9z-1)) = cos(6z + 1)
cos (90 - 9z+1)) = cos(6z + 1)
cos (91-9z) = cos(6z + 1)
Cos will cancel out to have;
91-9z = 6z+1
-9z - 6z = 1-91
-15z = -90
z = 90/15
z = 6
Hence the value of z is 6
True I think I am not Fr Fr tho
Hello,
Let's 2k-2,2k,2k+2 the 3 even integers
2k-2+(2k)+(2k+2)=30+2k-2
==>4k=28
==>k=7
The 3 integers ared 2*7-2=12, 2*7=14,2*7+2=16
12+14+16=42=30+12
Answer:
x = -1
Step-by-step explanation:
Only the solution x = -1 will work for this equation. The other solution is extraneous.