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Nutka1998 [239]
3 years ago
15

Can any one help me on these two please

Physics
1 answer:
Svetach [21]3 years ago
4 0
I THINK 5 is A and 6 is C
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This is the 3rd time I reposted this question lol.
Mamont248 [21]

Answer:

Blood absorbs nutrients and the waste products of cells. It carries waste away from cells and pumps nutrients through the whole body.

Explanation:

8 0
3 years ago
You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe
steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, L=800\ mH=800\times 10^{-3}\ H=0.8\ H

Capacitance, C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

Z=\sqrt{R^2+(X_C-X_L)^2}...........(1)

Where

X_C is the capacitive reactance, X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega

X_L is the inductive reactance, X_L={2\pi fL}

X_L={2\pi \times 60\times 0.8}=301.59\ \Omega

So, equation (1) becomes :

Z=\sqrt{(100)^2+(265.65-301.59)^2}

Z = 106.26 ohms

or

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

8 0
4 years ago
A ball of mass 0.10 kg moving at a speed of 3.0 m/s collides with a wall and bounces directly back with the same speed. If the b
alexdok [17]

The magnitude of the average force exerted on the ball by the wall is calculated below.

The average force exerted by the ball on the wall is 3 N

Explanation:

Given:

mass of the ball (m)=0.10 kg

speed (v) =3.0 m/s

time taken(t) =0.01 seconds

To calculate:

Average force(F) exerted by ball on the wall

We know;

F=(m×v)÷t

F=(0.10×3.0)÷0.01

<u><em>F=3 N</em></u>

Therefore the average force exerted by the ball on the wall is 3 N

8 0
4 years ago
Steep and unstable slopes can produce ____________ , forming coarse-grained rocks. magma erupted on the surface can form a _____
notka56 [123]

Steep and unstable slopes can produce LANDSLIDES AND MUDFLOWS , forming coarse-grained rocks.  

Landslides occur because of a compromise in the natural stability of a slope. It is characterized by masses of earth and rock rapidly moving down fast in the slant. Mudflows, are also a form of mass wasting attributed by extreme surging flow of liquefied debris and water.

-----------------------------------------------------------------------------------------------------------------

Magma erupted on the surface can form a LAVA FLOW that cools quickly, resulting in volcanic glass.  

Lava flow is a process in volcanic eruptions. Lava flows are oozing streams of molten rock from an erupting vent. Lava runs according to its type and viscosity, steepness of the landscape, whether the lava is flowing as a broad sheet through a tube or channel, and how rapid the production of lava is. When the lava cools immediately, it solidifies without crystallization and becomes a glasslike rock.

-----------------------------------------------------------------------------------------------------------------

Some volcanic ash rises vertically in an ERUPTION COLUMN , cools before accumulating on the surface, and forms deposits that are pegmatite.

Eruption column is emitted during an explosive eruption, as a column or a vertical cloud of ash and tephra in gases. It forms as crystalline granite measuring from several centimeters up to several meters high when it cools before accumulating.

-----------------------------------------------------------------------------------------------------------------

Some volcanic ash forms PYROCLASTIC FLOW that accumulate while hot and can become WELDED to some extent.

Pyroclastic flow is also referred to as pyroclastic density current or pyroclastic cloud. It is tephra as hot as 1000 degrees Celsius, swiftly moving away from the volcano speeding 700 km/h at most. Many pyroclastic flows that are thick become welded—compact and consolidated.


6 0
4 years ago
Read 2 more answers
1. (I) If the magnetic field in a traveling EM wave has a peak magnitude of 17.5 nT at a given point, what is the peak magnitude
Elan Coil [88]

Answer:

The electric field is E  =  5.25 V/m

Explanation:

From the question we are told that

    The peak magnitude of the magnetic field is  B  =  17.5 nT  =  17.5 *10^{-9}\ T

Generally the peak magnitude of the electric field is mathematically represented as

         E  =  c  *  B

Where c is the speed of light with value c  =  3.0 *10^{8} \ m/s

So

       E  =  3.0 *10^{8}  *  17.5 *10^{-9}

       E  =  5.25 V/m

8 0
4 years ago
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