Answer:
here, v = 0, a = - 9.8 m/sec^2, t = 3 sec
v = u + at
0 = u + (-9.8) * 3
0 = u - 29.4
u = 29.4 m/sec
here, u = 29.4m/s, t = 3sec, a= -9.8m/s^2
s = ut + 1/2 a t^2
s = 29.4 * 3 + 1/2 * - 9.8 * 3^2
s = 88.2 - 4.9 * 9
s = 88.2 - 44.1
s = 44.1 m
here, u = 0, a = 9.8m/s^2, t = 1 sec, s = ?
position after 4sec :
s = ut+ 1/2 at^2
s = 0 * 1 + 1/2 * 9.8 * 1^2
s = 4.9m
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The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
Learn more about conservation of momentum here:
brainly.com/question/7538238
Answer:
yes
Explanation:
Because they have logic duh!!! ;D
1) G.mars= 9.8x(1/3)=3.26
Vi=10 m/s , T=12 sec
Dis. = Vi(t)+1/2(g)(t)^2
(10)(12)+1/2(3.26)(12)^2= 354.72
2)V=500 m/s
Hmax= v^/2(g) = 500^2/2(9.8) = 12755.1