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4 years ago

15

Which function has the smallest x-intercept value, if it exists? A. f(x) = 3x – 9 B. f(x) = 1/x + 4 C. f(x) = root x+1 D. f(x) =

x2

2 answers:

kirza4 [7]4 years ago

8 0

Answer:

C

Step-by-step explanation:

yeah its C

sattari [20]4 years ago

4 0

Answer:

D is what I think

Step-by-step explanation:

It equals (0,0)

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1)
$F(x)=x^2+3x-10 \\
0=x^2+3x-10 \\
0=x^2-2x+5x-10 \\
0=x(x-2)+5(x-2) \\
0=(x+5)(x-2) \\
x+5=0 \ \lor \ x-2=0 \\
x=-5 \ \lor \ x=2 \\ \\
\hbox{the function has two zeroes: x=-5 and x=2}$

2)
$F(x)=-x^2+8x+9 \\
0=-x^2+8x+9 \\
0=-x^2-x+9x+9 \\
0=-x(x+1)+9(x+1) \\
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-x+9=0 \ \lor \ x+1=0 \\
x=9 \ \lor \ x=-1 \\ \\
\hbox{the function has two zeroes: x=-1 and x=9}$

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