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nirvana33 [79]
3 years ago
15

Which net matches the figure

Mathematics
2 answers:
Elza [17]3 years ago
4 0
Please post a picture of the net
Tamiku [17]3 years ago
3 0
You forgot to load the picture...
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Please help me with the answer!! There is the picture of the problem^
Gnoma [55]

Answer:

6

Step-by-step explanation:

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2 years ago
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25 Points: The probability of event A occurring in an experiment is P(A)=0.73
strojnjashka [21]

Answer:

.27

Step-by-step explanation:

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3 years ago
Gino brings home one book from each of his 5 school subjects and places them side by side on a
const2013 [10]

Answer:

about 50

Step-by-step explanation:

that's all I can think of

4 0
3 years ago
The equation 4x2 – 24x + 4y2 + 72y = 76 is equivalent to
DerKrebs [107]

Answer:

Option 4 is correct.

The equation 4x^2 -24x + 4y^2 + 72y = 76 is equivalent to 4(x-3)^2 + 4(y+9)^2 =436

Step-by-step explanation:'

Given equation: 4x^2 -24x + 4y^2 + 72y = 76

First group the terms with x and those with y;

(4x^2-24x)+(4y^2+72y) = 76

Next, we complete the squares.

We can do this by adding a third term such that the x terms and the y terms are perfect squares.

For this we must either add the same value on the other side of the equation or subtract the same value on the same side so that the equality is maintained.

⇒4(x^2-6x) +4(y+18y) = 76

or

4(x^2 -6x +3^2 -3^2) + 4(y^2 +18y +9^2 -9^2) = 76

4(x^2-6x + 3^2) - 36 + 4(y^2+18y +9^2) - 324 = 76

4(x-3)^2 + 4(y+9)^2 - 360 =76

Add 360 on both sides we get;

4(x-3)^2 + 4(y+9)^2 =360 +76

Simplify:

4(x-3)^2 + 4(y+9)^2 =436

Therefore, the given equation is equivalent to 4(x-3)^2 + 4(y+9)^2 =436

5 0
3 years ago
What can be used to determine the length of segment AB?
Vikki [24]

It depends on what you mean by "what can be used", you can use a protractor or ruler since it's a line segment. OR you can use the formula a^ + b^ = c^ to find out all the measurements.......

If you still can't find it, then, you can try to find the other measurements around that specific line segments. And it DEPENDS on what you choose to find the length of this segment.

( There's no picture on my screen, so I'm guessing that you didn't put any.. )

Well, I hope this can help you :3

STAY SAFE!! :)

6 0
3 years ago
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