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NeX [460]
3 years ago
7

How many seconds will tick away February 20th

Mathematics
1 answer:
Alborosie3 years ago
6 0
Approximately 86,400 seconds
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M is directly proportional to r3<br>When r = 4, M = 160<br>a) Work out the value of M when r = 2.​
Natali [406]

Answer:

M = 20

Step-by-step explanation:

Given that M is directly proportional to r³ then the equation relating them is

M = kr³ ← k is the constant of proportion

To find k use the condition when r = 4, M = 160, that is

160 = k × 4³ = 64k (divide both sides by 64 )

2.5 = k

M = 2.5r³ ← equation of proportion

When r = 2, then

M = 2.5 × 2³ = 2.5 × 8 = 20

6 0
3 years ago
Read 2 more answers
Find the number of faces, edges, and veritces of the solid​
Nesterboy [21]
This is probably wrong, but from what I know, there are 16 vertices, 24 edges, and 10 faces. I’m not sure if this is wrong, but I did some math and some research, and this is what I got.
7 0
3 years ago
Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of
serious [3.7K]

Answer:

i(x)=12 \times (1+\frac{0.9}{12})^{12x} and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 \times (1.9)^{x}, where x is the number of years.

Since, i(x)=12 \times (1.9)^{x}

i.e. i(x)=12 \times (1+0.9)^{x}.

Therefore, the monthly growth rate function becomes,

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}.

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Hence, the monthly growth rate is i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Also, the growth factor is given by \frac{0.9}{12} = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

4 0
3 years ago
Penny is 100 centimeters tall. Jeremy is 38 inches tall. Who is taller
NNADVOKAT [17]
1 inch = 2.54 cm
100 cm * (1 inch)/(2.54 cm) = 39.37 inches
Penny is taller
4 0
3 years ago
Read 2 more answers
The number of members on an organization increases by an average of 125 members annually. There were 3,875 members in 1971. Choo
Lena [83]

Answer:

B.

Mn = Mn-1 + 125 for n > 1 ; M1 = 3,875

Step-by-step explanation:

Since they tell us after 1970, the first data would be that of 1971 and also that if we started since 1970, we do not know the data of 1969, therefore answer B is correct.

Replacing:

Let M1 = 1971 then Mn-1, that is M0 = 1970, we know that the population of 1970 the population is 3750, because it would be 125 less than the subsequent year, and in 1975 there are 3875. Therefore:

in n = 1

 M1 = M0 + 125

3875 = 3750 + 125

this gives an equality, thus fulfilling the equation.

8 0
4 years ago
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