2 Points

The mass of the container is 5.81 kilograms when completely filled with sugar. The mass of the container is 3.8 kilograms when 3

blagie [28]

Removed sugar is 3/8 and it is 5.81-3.8=2.01 kg
so 3/8 is 2.01 kg
full mass of sugar is 2.01:3*8=5.6 kg
so the mass of container is 5.81-5.6=0.21 kg
Answer: the mass of <span>empty container is 0.21kg</span>

7 0

3 years ago

Four machines, each costing $5,700, were purchased for an office. Each machine requires

liubo4ka [24]

The number of months it would take to recover the cost of the machines is 12 months.

<h3> What is the total cost of the machines and the salary of the operators? </h3>

Total cost of the four machines = $5700 x 4 = $22,800

The total salaries of the machine operators in t months = 4t x $1,00 = $4,400t

Total cost = $22,800 + $4,400t

<h3>What is the amount saved by replacing the 8 clerks in t months? </h3>

($750 x 2t) + ($650 x 3t) + ($950 x 3t)

= $1500t + $1,950t +$2,850t

= $6300t

<h3>In how many months would it take to recover the cost of the machines? </h3>

$22,800 + $4,400t = $6300t

Combine similar terms

$22,800 = $6300t - $4400t

$22,800 = $1900t

Divide both sides by 1900

t = 12 months

To learn more about division, please check: brainly.com/question/194007

8 0

3 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$