Let the two numbers be x and y. The sum of x and y is 14 and the difference is 20. We can write a system of equations and solve:

Then substitute x back into one of the equations to find y:

So the two numbers are 17 and -3
Answer:
Sum of the sequence will be 648
Step-by-step explanation:
The given sequence is representing an arithmetic sequence.
Because every successive term of the sequence is having a common difference d = -3 - (-9) = -3 + 9 = 6
3 - (-3) = 3 + 3 = 6
Since last term of the sequence is 81
Therefore, by the explicit formula of an arithmetic sequence we can find the number of terms of this sequence

where a = first term of the sequence
d = common difference
n = number of terms
81 = -9 + 6(n - 1)
81 + 9 = 6(n - 1)
n - 1 = 
n = 15 + 1 = 16
Now we know sum of an arithmetic sequence is represented by

Now we have to find the sum of the given sequence
![S_{16}=\frac{16}{2}[-9 + (16-1)6]](https://tex.z-dn.net/?f=S_%7B16%7D%3D%5Cfrac%7B16%7D%7B2%7D%5B-9%20%2B%20%2816-1%296%5D)
= 8[-9 + 90]
= 8×81
= 648
Therefore, sum of the terms of the given sequence will be 648.
Step-by-step explanation:
AAA are the correct answer.
It is related to congurency.
Answer:
-49 is the answer for the question