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inysia [295]
3 years ago
12

The following dot plot represents a random sample of elementary students and the number of children that live in their home. If

this random sample is representative of elementary students in the United States, which of the following inferences can be made from the data? Select all that apply. The majority of the households in the United States, with at least one child, contain less than three children. Very few households in the United States contain four or more children. All households in the United States contain at least one child. None of the households in the United States contain five children.

Mathematics
2 answers:
9966 [12]3 years ago
6 0

Answer:

The majority of the households in the United States, with at least one child, contain less than three children.

Very few households in the United States contain four or more children.

And, None of the households in the United States contain five children.

Step-by-step explanation:

Hey so sorry this is late and if it's wrong I tried though-

ddd [48]3 years ago
4 0

Answer:

All households in the United States contain at least one child.

and None of the households in the United States contain five children.

Step-by-step explanation:this is what i awnsered sorry if its wrong

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Answer:

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It's 12 points of u get this right<br>​
earnstyle [38]

Answer:

y = -2x + 8

Step-by-step explanation:

When two points are given, the equation of the line passing through the points is given by:

        $ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} $

where: $ (x_1,y_1) $ and $ (x_2,y_2) $ are the two points passing through the line.

Here, $ (x_1,y_1) = (2,4) $ and $ (x_2, y_2) = (3,2) $.

Substituting in the formula, we have:

$ \frac{y - 4}{2 - 4} = \frac{x - 2}{3 - 2} $

⇒ $ \frac{y - 4}{-2} = \frac{x - 2}{1} $

⇒ y - 4 = -2x + 4

⇒ y = -2x + 8 is the required equation of the line.

4 0
3 years ago
If a plane can travel 490 miles per hour with the wind and 430 miles per hour against the​ wind, find the speed of the wind and
zavuch27 [327]

let the speed of plane in still air be x and that wind be y

therefore:

x+y=490

x-y=390

next we solve for the values of x and y, first we add the above equations. This will give us:

2x=880

x=880/2

x=440 miles per hour.

substituting the value of x in one of the equations and solving for y we get:

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"A" can solve 90% of the questions in a book and "B" can solve 70% of them.
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Step-by-step explanation:

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3 years ago
Read 2 more answers
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
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