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pishuonlain [190]
3 years ago
9

Consider the following balanced equation. SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table, showing the appropriate numb

er of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made. molSiO2 molC molSiC molCO _____ 9 _____ _____ 1 _____ _____ _____ _____ _____ _____ 26 _____ 7.5 _____ _____ 1.4 _____ _____ _____ Part A Complete the first row.
Chemistry
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

      3                          9                          3                                6

      1                           3                           1                                2

     13                         39                         13                             26

    2.5                        7.5                       2.5                            5.0

    1.4                         4.2                        1.4                            2.8

Explanation:

  • From the balanced equation:

<em>SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),</em>

  • It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.
  • We can complete the table of no. of moles of each component:

<u><em>1. 9.0 moles of C:</em></u>

We use the triple amount of C, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

<u><em>2. 1.0 mole of SiO₂:</em></u>

We use the same amount of SiO₂ as in the balnced equation, so the no. of moles of other components will be the same as in the balanced equation.

So, it will be 1.0 moles of SiO₂ with 3.0 moles of C that produce 1.0 moles of SiC and 2.0 moles of CO.

<u><em>3. 26.0 moles of CO:</em></u>

We use the amount of CO higher by 13 times than that in the balanced equation, so we multiply the others by 13.0.

So, it will be 13.0 moles of SiO₂ with 39.0 moles of C that produce 13.0 moles of SiC and 26.0 moles of CO.

<u><em>4. 7.5 moles of C:</em></u>

We use the amount of C higher by 2.5 times than that in the balanced equation, so we multiply the others by 2.5.

So, it will be 2.5 moles of SiO₂ with 7.5 moles of C that produce 2.5 moles of SiC and 5.0 moles of CO.

<u><em>5. 1.4 moles of SiO₂:</em></u>

We use the amount of SiO₂ higher by 1.4 times than that in the balanced equation, so we multiply the others by 1.4.

So, it will be 1.4 moles of SiO₂ with 4.2 moles of C that produce 1.4 moles of SiC and 2.8 moles of CO.

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Answer:

Molecular formula of ethylene glycol is C₂H₆O₂.

Explanation:

Given data:

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Molecular formula of ethylene glycol = ?

Solution:

percentage of carbon = (33.27 mg/ 23.46 mg) × (12 /44) × 100

                                      =  (1.4182× 0.27) × 100 = 38.29

percentage of hydrogen =  (20.42 mg/ 23.46 mg) × (2 /18) × 100

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percentage of oxygen = 100 - (38.29 + 9.67 )

                                      = 100 - 47.96 = 52.04

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 38.29 /12 = 3.19

No. of gram atoms of hydrogen = 9.67 / 1 = 9.67

No. of gram atoms of oxygen = 52.04 / 16 = 3.25

Atomic ratio:

     C :H :O               3.19/ 3.19    :   9.67 / 3.19   :  3.25 /3.19

     C :H :O                 1 : 3 : 1

Molecular formula:

    Molecular formula = n × (empirical formula)

    n = molar mass of compound / empirical formula mass

    empirical formula mass= 1 × 12 + 3 × 1  + 1 × 16

     empirical formula mass= 12+3 +16 = 31

                  n = 62 g /mol / 31 = 2

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From the chemical equation given:

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