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Ray Of Light [21]
2 years ago
11

Hg2(NO3)2 + Na2CO3 = NaNO3 + HgCO3 balance this

Chemistry
1 answer:
Elenna [48]2 years ago
4 0

Answer:

Hg(NO3)2 + Na2CO3 --> 2NaNO3 + HgCO3

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A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h
statuscvo [17]

Explanation:

First, calculate the moles of CO_{2} using ideal gas equation as follows.

                PV = nRT

or,          n = \frac{PV}{RT}

                = \frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}      (as 1 bar = 1 atm (approx))

                = 0.183 mol

As,   Density = \frac{mass}{volume}

Hence, mass of water will be as follows.

                Density = \frac{mass}{volume}

             0.998 g/ml = \frac{mass}{3.26 ml}    

                 mass = 3.25 g

Similarly, calculate the moles of water as follows.

        No. of moles = \frac{mass}{\text{molar mass}}

                              =  \frac{3.25 g}{18.02 g/mol}            

                              = 0.180 mol

Moles of hydrogen = 0.180 \times 2 = 0.36 mol

Now, mass of carbon will be as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

          0.183 mol =  \frac{mass}{12 g/mol}            

                              = 2.19 g

Therefore, mass of oxygen will be as follows.

              Mass of O = mass of sample - (mass of C + mass of H)

                                = 3.50 g - (2.19 g + 0.36 g)

                                = 0.95 g

Therefore, moles of oxygen will be as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                               =  \frac{0.95 g}{16 g/mol}            

                              = 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

                         C              H           O

No. of moles:  0.183        0.36       0.059

On dividing:      3.1           6.1            1

Therefore, empirical formula of the given compound is C_{3}H_{6}O.

Thus, we can conclude that empirical formula of the given compound is C_{3}H_{6}O.            

6 0
3 years ago
How do I balance a chemical reaction like one of these NaBr + Ca(OH)2 ➡️ CaBr2 + NaOH
mojhsa [17]
2NaBr + Ca(OH)2 ➡️ CaBr2 + 2NaOH
3 0
3 years ago
The digit that would have to be estimated in reading this instrument would be the nearest:
wariber [46]

Answer:

The least count of vernier calipers is 0.01 g.

(B) is correct option.

Explanation:

Given that,

The digit that would have to be estimated in reading this instrument,

According to figure,

We need to calculate the pitch

Using formula of pitch

pitch=\dfrac{distance\ moved}{Number\ of\ complete\ rotation}

Put the value into the formula

pitch=\dfrac{1}{10}

pitch=0.1\ g

We need to calculate the least count of vernier calipers

Using formula of least count

Least\ count=\dfrac{pitch}{number\ of\ vernier\ scale\ division}

Put the value into the formula

Least\ count=\dfrac{0.1}{10}

Least count = 0.01\ g

Hence, The least count of vernier calipers is 0.01 g.

(B) is correct option.

4 0
3 years ago
Read 2 more answers
The Bay of Fundy in Nova Scotia, Canada is reported to have the largest tides in the world with high tide and low tide occurring
topjm [15]

The rate in m/s is 5.2 * 10^-4 m/s.

<h3>What is the rate in m/s?</h3>

We know that the speed is given as the ratio of the distance covered to the time taken. In this case, we have been told that the rate at which the tide rises is 6.08 ft per hour. We would now need to convert the rate from  6.08 ft per hour to m/s.

Now;

We know that;

1 foot/hour = 8.5 * 10^-5 m/s

6.08 ft per hour = 6.08 ft per hour * 8.5 * 10^-5 m/s/1 foot/hour

= 5.2 * 10^-4 m/s

Learn more about speed:brainly.com/question/28224010

#SPJ1

3 0
2 years ago
Explain why this reaction can be classified as a synthesis reaction
rusak2 [61]
The reason why the reaction written on the picture can be classified as a synthesis reaction is :
the reaction shows one compound that formed from two compounds 

hope this helps
5 0
3 years ago
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