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kap26 [50]
1 year ago
11

Oxidation state of Nitrogen in N2O5​

Chemistry
1 answer:
balandron [24]1 year ago
7 0

Explanation:

Oxidation state of Nitrogen in N2O5 is +5

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Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma
Katen [24]

Answer: 12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.

Explanation:

moles =\frac{\text {given mass}}{\text {Molar mass}}

moles of zinc =\frac{2.55g}{65.38g/mol}=0.0390moles

The balanced chemical equation is :

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to stoichiometry:

1 mole of zinc reacts with = 2 moles of HCl

Thus 0.0390 moles of zinc reacts with = \frac{2}{1}\times 0.0390=0.0780 moles of HCl

To calculate the volume for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}     .....(1)

Molarity of HCl solution = 6.50 M

Volume of solution = ?

Putting values in equation 1, we get:

6.50M=\frac{0.0780\times 1000}{\text{Volume of solution in ml}}

{\text{Volume of solution in ml}}=12.0ml

Thus 12.0 ml of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn

3 0
3 years ago
Propane has a normal boiling point of -42.04 °C and a heat of vaporization of 24.54 kJ/mole. What is the vapor pressure of propa
Mademuasel [1]

Answer : The vapor pressure of propane at 25.0^oC is 17.73 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of propane at 25.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 25.0^oC=273+25.0=298.0K

T_2 = normal boiling point of propane = -42.04^oC=230.96K

\Delta H_{vap} = heat of vaporization = 24.54 kJ/mole = 24540 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{24540J/mole}{8.314J/K.mole}\times (\frac{1}{298.0K}-\frac{1}{230.96K})

P_1=17.73atm

Hence, the vapor pressure of propane at 25.0^oC is 17.73 atm.

3 0
3 years ago
Molecular compounds are capable of forming multiple covalent bonds. the compound below that contains a triple bond is:
alexira [117]

The answer is <u>CO(g).</u>

4 0
1 year ago
I need help with everything
maria [59]
For the hypothesis put what you think will happen
6 0
3 years ago
To find the number of neutrons in a atom, you subtract the number of_____ from the mass number.
Slav-nsk [51]

You can simply subtract the atomic number from the mass number in order to find the number of neutrons.

8 0
2 years ago
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