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3 years ago

I need to know 6.39/9 is?

Mathematics

1 answer:

Advocard [28]3 years ago

8 0

Answer:

The answer on my calculator is 0.71. I just divided 6.39 by 9 and got the answer. If you need more help let me know!

Step-by-step explanation:

You might be interested in

How do you solve this system of equation? 2x+4y=-4 3x + 5y =-3

Annette [7]

Answer:

x = 4

y = -3

Step-by-step explanation:

We can use substitution, elimination, or graphically.

Step 1: Rearrange first equation

2x + 4y = -4

2x = -4 - 4y

x = -2 - 2y

Step 2: Rewrite systems of equations

x = -2 - 2y

3x + 5y = -3

Step 3: Substitution

3(-2 - 2y) + 5y = -3

-6 - 6y + 5y = -3

-6 - y = -3

-y = 3

y = -3

Step 4: Find x using y

2x + 4(-3) = -4

2x - 12 = -4

2x = 8

x = 4

Graphically:

Use a graphing calc and analyze where the 2 lines intersect.

5 0

4 years ago

True or false ???????????????please help

Dovator [93]

1 True because 19^3 = 6859
2. False
3. True because 8000 ^1/3 can be written as 100^1/3 * 8^1/3
4 False
5 True because they are both = 15

If you have a scientific calculator you can check these out yourself

7 0

4 years ago

What is the answer to ax + 7 = 8x + b when x=9

xxTIMURxx [149]

Hey there!

ax + 7 = 8x + b

when x=9, so:

a(9) +7= 8(9) +b

9a +7= 72+b

I hope this helps?

6 0

4 years ago

Suppose the wholesale price of a certain brand of medium-sized eggs p (in dollars/carton) is related to the weekly supply x (in

Mrrafil [7]

Answer:

1300

Step-by-step explanation:

We are given

x = 35

$\frac{dp}{dt}=-0.05$ [rate of change of price with time]

We want to find $\frac{dx}{dt}$ , which is the rate at which supply is changing.

First, we need to implicitly differentiate the equation given:

$625p^2-x^2=100\\1250p\frac{dp}{dt}-2x\frac{dx}{dt}=0$

Here, we have what we need except for p. We find p when x = 35:

$625p^2 - x^2 =100\\625p^2 - (35)^2 =100\\625p^2=1325\\p=1.46$

Now, find dx/dt:

$1250(1.46)(-0.05)-2(35)\frac{dx}{dt}=0\\-91.25-70\frac{dx}{dt}=0\\\frac{dx}{dt}=-1.30$

In thousands, 1.30 * 1000 = 1300 cartons per week decrease

5 0

3 years ago

The exterior walls and roof of a barn are to be painted. The barn is in the shape of a rectangular prism, with an isosceles tria

vlada-n [284]

Given:

The rectangular prism has a length of 25 feet, a width of 10 feet and a height 55 feet.

The triangular prism has a base length of 25 feet, a height of 8 feet, and a prism height of 55 feet.

To find:

The total area to be painted.

Solution:

There are 4 external surfaces for the rectangular prism and 4 external surfaces for the triangular prism.

The rectangular prism has 4 rectangles out which there are 2 sets of similar rectangles.

There are two rectangles with lengths of 25 feet and widths of 10 feet while the other two rectangles have lengths of 55 feet and widths of 10 feet.

The area of a rectangle with a length of 25 feet and a width of 10 feet $= 25(10)= 250$ square ft.

The area of two such rectangles $= 2(250) = 500$ square feet.

The area of a rectangle with a length of 55 feet and a width of 10 feet $= 55(10)= 550$ square feet.

The area of two such rectangles $= 2(550) = 1100$ square feet.

The triangular prism has 2 triangles and 2 rectangles.

The triangles have base lengths of 25 feet and heights of 8 feet while the rectangles have lengths of 55 feet and heights of 14.8 feet.

The area of a triangle with a base length of 25 feet and a height of 8 feet $= \frac{1}{2}(25)(8)= 100$ square feet.

The area of two such triangles $=2(100)= 200$ square feet.

The area of a rectangle with a length of 55 feet and a width of 14.8 feet $= 55(14.8)= 814$ square feet.

The area of two such rectangles $= 2(814) = 1628$ square feet.

The total area to be painted $=500+1100+200+1628 = 3128$ square feet.

So an area of 3128 square feet is to be painted.

8 0

3 years ago