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Rasek [7]
3 years ago
8

You are to drive to an interview in another town, at a distance of 270 km on an expressway. The interview is at 11:15 a.m. You p

lan to drive at 100 km/h, so you leave at 8:00 a.m. to allow some extra time. You drive at that speed for the first 110 km, but then construction work forces you to slow to 42.0 km/h for 43.0 km. What would be the least speed needed for the rest of the trip to arrive in time for the interview?
Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

the least required speed  is 103.88 km/h

Step-by-step explanation:

Data provided in the question:

Total distance = 270 km

Total time to reach = Time between 8 a.m and 11:15 a.m i.e 3.25 hours

Now,

For the distance of 110 km speed was 100 km/h

therefore, the time taken to cover 110 km = \frac{\textup{Distance}}{\textup{speed}}

= \frac{\textup{110 km}}{\textup{100 km/h}}

= 1.1 hour

For another 43 km speed was 42 km/h

therefore, the time taken to cover 43 km =  \frac{\textup{Distance}}{\textup{speed}}

= \frac{\textup{43 km}}{\textup{42 km/h}}

= 1.0238 hours

Now,

The distance left to be covered = 270 - 110 - 43 = 117 km

Time left = 3.25 h - 1.1 h - 1.0238 h = 1.1262 h

Thus required speed = \frac{\textup{117 km}}{\textup{1.1262 h}}

= 103.88 km/h

Hence, the least required speed  is 103.88 km/h

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IrinaVladis [17]

The line has a positive slope. Let's look at all the slopes:

1) -3

2) -3

3) 3

4)3

Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.

The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.

1) y = -3/2x - 5/2

2) y = -3/2x + 5/2

We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.

The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.

5 0
3 years ago
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Olegator [25]
Answer: Choice C) 

--------------------------------------

mean = xbar = (2400+1750+1900+2500+2250+2100)/6
mean = 2150

Subtract the data values from the mean to get

2400-2150 = 250
1750-2150 = -400
1900-2150 = -250
2500-2150 = 350
2250-2150 = 100
2100-2150 = -50
The differences are: 250, -400, -250, 350, 100, -50 

Then you square those values and add up the squares

(250)^2 +  (-400)^2 +  (-250)^2 +  (350)^2 +  (100)^2 +  (-50)^2 = 420,000
3 0
3 years ago
Read 2 more answers
The slope of a line that is parallel to each line whose equation is given
Kobotan [32]
Parallel lines, slope is the same so
1) 3x+8y = 12
8y = -3x + 12
  y = -3/8(x) + 3/2, slope = -3/8

slope of a line that is parallel = -3/8

2)5x+4y = 5
  4y = -5x + 5
    y = -5/4(x) + 5/4; slope is -5/4

slope of a line that is parallel = -5/4
--------------------
perpendicular, slope is opposite and reciprocal

3)
3x+8y = 11
 8y = -3x + 11
   y = -3/8(x) + 11/8. slope = -3/8
slope of perpendicular line = 8/3

4)
x = -7, slope is undefined
so slope of perpendicular line is 0

5)
3x+2y = 12
2y = -3x + 12
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5x - 6y = 8
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slope is opposite and reciprocal, so the equals are perpendicular

6)
3x + y = 5
y = -3x + 5; slope = -3

6x + 2y = -15
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3 years ago
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Aleksandr [31]

HERE IS YOUR ANSWER HOOMAN:

8

STEP BY STEP EXPLANATION FAM:

We have a set of four numbers and the mean is 5. We can see that the sum of the values is 20:

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We have another set of three numbers whose mean is 12. We can write that as:

\frac{36}{3}=12

To find the mean of the seven numbers together, we can add the values together and divide by 7:

\frac{20+36}{7}=\frac{56}{7}=8

HOPE DIS HELPED FAM  

w(゚Д゚)w

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yawa3891 [41]

Answer:

Does the answer help you?

please mark this question as brainliest answer.Cause it take a few mins to solve your question.Tq

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