1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rasek [7]
2 years ago
8

You are to drive to an interview in another town, at a distance of 270 km on an expressway. The interview is at 11:15 a.m. You p

lan to drive at 100 km/h, so you leave at 8:00 a.m. to allow some extra time. You drive at that speed for the first 110 km, but then construction work forces you to slow to 42.0 km/h for 43.0 km. What would be the least speed needed for the rest of the trip to arrive in time for the interview?
Mathematics
1 answer:
Yuri [45]2 years ago
6 0

Answer:

the least required speed  is 103.88 km/h

Step-by-step explanation:

Data provided in the question:

Total distance = 270 km

Total time to reach = Time between 8 a.m and 11:15 a.m i.e 3.25 hours

Now,

For the distance of 110 km speed was 100 km/h

therefore, the time taken to cover 110 km = \frac{\textup{Distance}}{\textup{speed}}

= \frac{\textup{110 km}}{\textup{100 km/h}}

= 1.1 hour

For another 43 km speed was 42 km/h

therefore, the time taken to cover 43 km =  \frac{\textup{Distance}}{\textup{speed}}

= \frac{\textup{43 km}}{\textup{42 km/h}}

= 1.0238 hours

Now,

The distance left to be covered = 270 - 110 - 43 = 117 km

Time left = 3.25 h - 1.1 h - 1.0238 h = 1.1262 h

Thus required speed = \frac{\textup{117 km}}{\textup{1.1262 h}}

= 103.88 km/h

Hence, the least required speed  is 103.88 km/h

You might be interested in
If u(x) = x^5 – x^4 + x^2 and v(x) = –x^2, which expression is equivalent to (u/v)(x)?
Effectus [21]
Hello: 
x^5 – x^4 + x^2 =x^2(x^3 - x^2 +1)
(u/v)(x)= x^2(x^3 - x^2 +1)/(-x^2)
(u/v)(x)= - (x^3 - x^2 +1) = -x^3+x^2-1    (  x :  no zero)
7 0
3 years ago
A science fair poster is a rectangle 3 feet long and 2 feet wide. What is the area of the poster in square inches? Be sure to in
vredina [299]
Area = length · width
Area = 3ft · 2ft
Area = 6ft²

hope this helps!
5 0
3 years ago
HELP!!! 30 points!
user100 [1]
Basically, the equator is like the x-axis of the world and the prime meridian is like the y-axis. You locate places by distances from these lines.
7 0
3 years ago
Read 2 more answers
How do you compare 492,111 and 409,867
ExtremeBDS [4]
By adding an < or >.
6 0
3 years ago
Read 2 more answers
13 feet in 5 steps plss
Mashutka [201]

Answer:

2.6 feet per step

Step-by-step explanation:

8 0
2 years ago
Other questions:
  • How to write an indirect statement that a scalene traingle cannot have two congruent midsegments
    11·1 answer
  • 12,00 equals how many hundreds?
    6·2 answers
  • Boxes that are 12 inches tall are being stacked next to boxes that are 18 inches tall. What is the shortest height qt which the
    5·1 answer
  • What are two decimals that are equivalent to 7.7
    14·1 answer
  • A stack of 500 sheets of paper is 3 inches in height.What is the thicknrss of one sheet of paper,in inches?Answer with supportin
    14·1 answer
  • Solve 2x +7y = 4 for y
    9·1 answer
  • ?<br> Find the measure of the missing angles.<br> 146<br> ba<br> Submit Answer<br> attempts out of 2
    11·1 answer
  • Heres 5 freepoints to the first 2 dedicated people that r stll wake
    8·2 answers
  • 2w^2-11w+12=0 solve using Quadratic
    15·2 answers
  • Need help on this one.<br> I JUST DONT WHAT TO DO IT
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!