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Marina CMI [18]
3 years ago
13

Please Help

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

1.2

Step-by-step explanation:

You simply have to look for a point on the graph that has an x-coordinate of -6. Only one is (-6. 1.2), so 1.2 is your answer.

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Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dis
Ronch [10]
<h2><u>Complete Question: </u></h2>

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dissimilar.

1. \frac{2}{3} $ and $ \frac{1}{3}

2. \frac{3}{4} $ and $ \frac{1}4}

3. \frac{4}{7} $ and $ \frac{7}{8}

4. \frac{2}{5} $ and $ \frac{5}{11}

5. \frac{7}{13} $ and $ \frac{7}{9}

<h2><em><u>The answers:</u></em></h2>

1. \frac{2}{3} $ and $ \frac{1}{3} - Similar (S)

2. \frac{3}{4} $ and $ \frac{1}4} - Similar (S)

3. \frac{4}{7} $ and $ \frac{7}{8} - Dissimilar (D)

4. \frac{2}{5} $ and $ \frac{5}{11} - Dissimilar (D)

5. \frac{7}{13} $ and $ \frac{7}{9} - Dissimilar (D)

Note:

  • Similar fractions have the same denominator. i.e. the bottom value of both fractions are the same.
  • Dissimilar fractions have different value as denominator, i.e. the bottom value of both fractions are not the same.

Thus:

1. \frac{2}{3} $ and $ \frac{1}{3} - They have equal denominator. <u><em>Both fractions are similar (S).</em></u>

2. \frac{3}{4} $ and $ \frac{1}4} - They have equal denominator. <em><u>Both fractions are similar (S).</u></em>

3. \frac{4}{7} $ and $ \frac{7}{8} - They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>

4. \frac{2}{5} $ and $ \frac{5}{11} - They have equal denominator. <u><em>Both fractions are dissimilar (D).</em></u>

5. \frac{7}{13} $ and $ \frac{7}{9} - They have equal denominator. <em><u>Both fractions are dissimilar (D).</u></em>

Therefore, the fractions in <em><u>1 and 2 are similar (S)</u></em> while those in <em><u>3, 4, and 5 are dissimilar (D).</u></em>

<em><u></u></em>

Learn more here:

brainly.com/question/22099172

7 0
3 years ago
Which one is right i need this fast
Over [174]

Answer:

The answer for the question is A, D and E

8 0
4 years ago
Read 2 more answers
Determine the number of solutions for the equation: -6(24x+18)=43(5+5x).
Agata [3.3K]
The answer is B 

<span>-6(24x+18)=43(5+5x)
-144x - 108 = 215 +215x
-108 = 215 + 359x
-323 = 359x 
-323/359 = x

If you would like me to explain more details i will!</span>
3 0
4 years ago
Read 2 more answers
Determine which set of side measurements could be used to form a right triangle.
Dmitry_Shevchenko [17]

The sets (\sqrt{7}, 4, \sqrt{23}) and(\sqrt{29}, \sqrt{39}, 68) could be used to form a right triangle.

What is right triangle?

A right triangle, also known as a right-angled triangle, an orthogonal triangle, or historically a rectangled triangle, is a triangle with one right angle, meaning that its two sides are perpendicular. Trigonometry's foundation is the relationship between the right triangle's sides and other angles.

Since for the right triangle is a, b, c are three sides of a triangle, where c is the diagonal, then

a^2 + b^2 = c^2

Consider, the set  (3, 5, 8)

Here,  3^2 + 5^2 ≠ 8^2.

Consider, the set (8, 9, 11)

Here, 8^2 + 9^2 ≠ 11^2

Consider, the set (\sqrt{7}, 4, \sqrt{23})

Here, (\sqrt{7})^2 + 4^2 = (\sqrt{23})^2

Consider, the set (\sqrt{29}, \sqrt{39}, 68)

Here, (\sqrt{29})^2 + (\sqrt{39})^2 = 68

Hence, (\sqrt{7}, 4, \sqrt{23}), (\sqrt{29}, \sqrt{39}, 68) could be used to form a right triangle.

To know more about the right triangle, click on the link

brainly.com/question/2437195

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4 0
1 year ago
Read 2 more answers
6х + 4ув 32<br>-6х + 4 y = 8​
AveGali [126]

Answer:

The Solution set is (x,y){(2,5)}

Step-by-step explanation:

The given equation is:

  6x+4y=32

 -6x+4y=8

We will use the elimination method:

By this method we will eliminate the variable x.

6x+4y=32

-6x+4y=8

________

      8y=40

Divide both the sides by 8

8y/8=40/8

y=5

Now substitute the value of y in equation 2:

-6x+4y=8

-6x+4(5)=8

-6x+20=8

Move the constant value to the R.H.S

-6x=8-20

-6x= -12

Divide both the terms by -6

-6x/-6 = -12/-6

x= 2

The Solution set is (x,y){(2,5)}....

6 0
3 years ago
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