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Elden [556K]
3 years ago
10

The LCM of three numbers is 7920 and their GCD is 12. Two of the numbers are 48 and 264. Using factor notation find the third nu

mber if one of its factors is 9.
Mathematics
1 answer:
Lelechka [254]3 years ago
6 0

Answer:

The third number is 180.

Step-by-step explanation:

Let the third number be 9x where x is an integer.

48 = 2*2*2*2*3

264 = 2*2*2*3*11

9x = 3*3*x

2*2*2*2*3*3*11*x = 7920y where y is an integer

1584x = 7920y

so x = 7920y / 1584= 5y.

Now the GCD is 12  so x must have  4 as one of its factors.

Also x is a multiple of 5 so it could be 20 then y  would be 4.

If x = 20 then the third number is 9*20 = 180.

This checks out OK.

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=============================================================

Explanation:

For now, I'll treat n as x, and M as y.

In other words,

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Let's select two points from this graph. I'll pick (200,150) and (400,200)

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You could also use (x,y) = (400,200) and you should get the same b value.

In fact, any other point from this graph works as well.

------------------------------

Since m = 0.25 and b = 100, we go from y = mx+b to y = 0.25x+100

This then translates over to M = 0.25n + 100 which is choice A

To help verify this, let's say we plugged in n = 100

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M = 0.25*100 + 100

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