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Paraphin [41]
3 years ago
11

Zane each one eighth of a pizza later he is a half of the same Pizza to eat more the first time or the second time

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
3 0
Second time. hope this helped
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A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
2 years ago
An a adult ticket to the zoo costs $20 and a child’s ticket costs $10.How much will it cost for Mr. and Mrs.Brown and their 4 ch
liubo4ka [24]

Answer:

Step-by-step explanation:

you add 20 for mr brown 20 for mrs brown 10 for kid one 10 for kid 2 ten for kid 3 and 10 for kid for giving you a grand total of 80 dollars

5 0
2 years ago
Read 2 more answers
A microgram is equal to 2.3 x 10 grams. How many times greater than a microgram is
vovikov84 [41]

Answer:

yes the aswure is no

Step-by-step explanation:

8 0
2 years ago
5 1/6 + (7 1/3)l <60
agasfer [191]

Answer:

l

Step-by-step explanation:

Given the inequality

5\dfrac{1}{6}+7\dfrac{1}{3}l

First, convert mixed numbers to improper fractions:

5\dfrac{1}{6}=\dfrac{5\cdot 6+1}{6}=\dfrac{31}{6}\\ \\7\dfrac{1}{3}=\dfrac{7\cdot 3+1}{3}=\dfrac{22}{3}

Now the inequality looks like

\dfrac{31}{6}+\dfrac{22}{3}l

Multiply it by 6:

\dfrac{31}{6}\cdot 6+\dfrac{22}{3}l\cdot 6

7 0
3 years ago
I'm confused on #21. It's very hard. I tried starting it but I gave up.
UkoKoshka [18]
Can't read the full question
7 0
2 years ago
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