Complete question:
Point charges q1=- 4.10nC and q2=+ 4.10nC are separated by a distance of 3.60mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30×10−9 N⋅m ? Express your answer in newtons per coulomb to three significant figures.
Answer:
The magnitude of this field is 826 N/C
Explanation:
Given;
The torque exerted on the dipole, T = 7.3 x 10⁻⁹ N.m
PEsinθ = T
where;
E is the magnitude of the electric field
P is the dipole moment
First, we determine the magnitude dipole moment;
Magnitude of dipole moment = q*r
P = 4.1 x 10⁻⁹ x 3.6 x 10⁻³ = 1.476 x 10⁻¹¹ C.m
Finally, we determine the magnitude of this field;
E = 826 N/C (in three significant figures)
Therefore, the magnitude of this field is 826 N/C
Answer:
Approximately 
, assuming that the volume of these two charged objects is negligible.
Explanation:
Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.
Let 
and 
denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, 
and 
.
Let 
denote the distance between these two point charges. In this question, 
.
Let 
denote the Coulomb constant. In standard units, 
.
By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:
.
Substitute in the values and evaluate:
.
Answer:
e. The net magnetic flux in this case would be equal to zero.
Explanation:
As per Gauss law of magnetism we need to find the net magnetic flux through a closed loop
here we know that net magnetic flux is the scalar product of magnetic field vector and area vector
so here we have
= net magnetic flux
since we know that magnetic field always forms closed loop so if we find the integral over a closed loop
then in that case the value of the close integral must be zero
so correct answer would be
e. The net magnetic flux in this case would be equal to zero.
C. Is the da answer to your question!
Answer:
Explanation:
Given
W amount of work is done on the system such that it acquires v velocity after operation(initial velocity)
According to work energy theorem work done by all the forces is equal to change in kinetic energy of object
where m=mass of object
v=velocity of object
When the object is already have velocity v then the final speed is given by work energy theorem
From 1 and 2 we get
