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Andrei [34K]
3 years ago
9

4. The Mariana trench is in the Pacific Ocean and has a depth of approximately 11,000 m. The density of seawater is approximatel

y 1025 kg/m3. What force would someone experience at such depth?
Physics
1 answer:
Alex73 [517]3 years ago
3 0

Explanation:

It is known that relation between pressure and density is as follows.

            P = \rho gh

where,    P = pressure

     \rho = density

            g = acceleration due to gravity

            h = height

Putting the given values into the above formula as follows.

              P = \rho gh

                 = 1025 \times 9.8 \times 11000

                 = 110495000 Pa

Now, relation between pressure and force is as follows.

                P = \frac{F}{A}

or,            F = PA

                F = 110495000 \times \pi \times (0.1)^{2}

                   = 3.47 \times 10^{6} N

Thus, we can conclude that a force of 3.47 \times 10^{6} N can be  experienced at such depth.

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A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.1 m/s. The drag force is of the form bv2 What is the value of b?
meriva
At terminal velocity, drag force becomes equal to weight. Therefore:
weight = bv²
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3 years ago
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The St. Louis Arch has a height of 192 m. Suppose that a stunt woman of mass 84 kg jumps off the top of the arch with an elastic
Hitman42 [59]

To solve this problem it is necessary to apply the kinematic equations of motion for speed and distance, as well as the concepts related to kinetic energy.

The change in the height of a body subject to gravity is given by

h = \frac{1}{2} gt^2 \rightarrow t = \sqrt{\frac{2h}{g}}

Where

h = Height

g =Gravity

t = time

Replacing with our values we have that the time is

t = \sqrt{\frac{2h}{g}}

t = \sqrt{\frac{2(192)}{9.8}}

t = 6.25s

From speed as a function of change between acceleration and time we have then that after 2.6 seconds the speed would be

g = \frac{v}{t} \rightarrow v = g*t

v = 9.8*2.6

v = 25.48m/s

The kinetic energy would be given by

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (84)(25.48)

KE = 1070.16J

Therefore the kinetic energy after 2.6s is 1070.16J

6 0
3 years ago
Which of the following describes one of the main features of wave-particle duality?
steposvetlana [31]
<h2>Answer:  as mass increases, the wave nature of matter is less easy to observe.</h2>

At the beginning of the 20th century the French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>

In this sense, the de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p}   (1)

Where:

h is the Planck constant

p is the momentum of the atom, which is given by:

p=m.v (2)

Where:

m is the mass

v is the velocity

Substituting (2) in (1):

\lambda=\frac{h}{m.v}[\tex]   (3)As we can see, if we increase the mass, the wavelength decreases (because [tex]\lambda is inversely proportional to m).

Therefore, if the wavelength decreases the wave nature of matter is less easy to observe.

The other options are incorrect because:

a) as v increases \lambda decreases and the particle nature matter becomes more evident

b) as p decreases \lambda increases and the wave nature matter becomes more evident

c) There is also a relation between the wavelength and the energy E:

\lambda=\frac{hc}{E}

So, as energy increases, the particle nature matter becomes more evident and the wave nature of matter becomes harder to observe

8 0
4 years ago
You have just landed on Planet X. You release a 100-g ball from rest from a height of 10.0 m and measure that it takes 3.40 s to
Nana76 [90]

Answer:

w = 0.173 N

Explanation:

The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.

The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:

y(t) = v_0 * t + y_0 - 0.5 * g * t^2

y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.

v_0 is the initial velocity, in this case v_0 = 0 m/s.

y_0 is the initial position of the ball, in this case it is 10 m.

g is the gravity that we want to know.

Applying these values in the equation we have:

0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2

0 = 10 - 0.5*11.56*g

0 = 10 -5.78*g

5.78*g = 10

g = 1.73 m/s^2

Then we can use this value to find out the weigh of the ball in that planet:

w = g*m = 0.1*1.73 = 0.173 N

6 0
4 years ago
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