Answer:
Explanation:
It is a question relating to charging of capacitor . For charging of capacitor , the formula is as follows.
Q = CV ( 1 - )
λ = 1/CR , C is capacitance and R is resistance.
= 1/(500 x 10⁻⁶ x 20 x 10³ )
= .1
λ t = .1 x 20
λ t = 2
CV = 500 X 10⁻⁶ X 5
= 2500 X 10⁻⁶ C
Q = 2500 x 10⁻⁶ ( 1 - )
= 2500 x 10⁻⁶ x .86566
= 2161.66 μ C .
voltage = Charge / capacitor
2161.66 μ C / 500μ F
= 4.32 V
Answer:
The motion of the block is downwards with acceleration 1.7 m/s^2.
Explanation:
First, we will calculate the acceleration using the kinematics equations. We will denote the direction along the incline as x-direction.
Newton’s Second Law can be used to find the net force applied on the block in the -x-direction.
Now, let’s investigate the free-body diagram of the block.
Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,
As for the static friction, we will consider the angle 31.8, but just before the block starts the move.