Answer:
1092 J
Explanation:
From the question,
Assuming no heat is lost to the surrounding
Heat lost by the metal = Heat gained by water.
H' = Cm(t₂-t₁)................. Equation 1
Where H' = Heat lost by the metal, C = specific heat capacity of water, m = mass of water, t₂ = Final temperature of the mixture, t₁ = Initial temperature of water
But,
m = D'v................... Equation 2
Where D' = Density of water, v = volume of water.
Given: D' = 1000 kg/m³, v = 100 mL = 100/1000000 = 0.0001 m²
Substitute into equation 2
m = 1000(0.0001)
m = 0.1 kg.
Also given: C = 4200 J/kg.°C, t₁ = 22 °C, 24.6 °C
Substitute into equation 1
H' = 4200×0.1×(24.6-22)
H' = 420(2.6)
H' = 1092 J.
Hence the heat (q) lost by the metal = 1092 J
Answer:
16 times as strong
Explanation:
From the question given above, the following assumptions were made:
Initial Force (F₁) = F
Initial distance apart (r₁) = r
Final distance apart (r₂) = ¼r
Final force (F₂) =?
Next, we shall obtain a relationship between the force and the distance apart. This can be obtained as follow:
F = GM₁M₂ / r²
Cross multiply
Fr² = GM₁M₂
If G, M₁ and M₂ are kept constant, then,
F₁r₁² = F₂r₂²
Finally, we determine the new force as follow:
Initial Force (F₁) = F
Initial distance apart (r₁) = r
Final distance apart (r₂) = ¼r
Final force (F₂) =?
Fr² = F₂ × (¼r)²
Fr² = F₂ × r²/16
Fr² = F₂r² / 16
Cross multiply
16Fr² = F₂r²
Divide both side by r²
F₂ = 16Fr² / r²
F₂ = 16F
From the calculations made above, we can see that the new force is 16 times the original force.
Thus, the new force is 16 times stronger.
The answer is C because carbon dioxide is trapped in a thick atmosphere.
Refrigerator was what is commonly used today. We do dry foods and salt cure but that is not done on a daily basis
To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:
Where,
B= Magnetic Field
l = length
= Vacuum permeability
= Vacuum permittivity
Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to
Recall that the speed of light is equivalent to
Then replacing,
Our values are given as
Replacing we have,
Therefore the magnetic field around this circular area is
