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BabaBlast [244]
3 years ago
6

Find the sum of the vectors:11 km N ,11km E

Physics
1 answer:
vladimir1956 [14]3 years ago
6 0

The resultant vector is 11√2 km due north east.

<h3><u>Explanation:</u></h3>

The vector is a type of quantity which has both magnitude and direction. This quantities when expressed needs to specify both magnitude and direction.

We need to calculate the magnitude and direction separately.

Here firstly for the magnitude,

The magnitudes are both 11 km and they are at right angles to each other.

So, the resultant magnitude = √(11² +11²) km

=11√2 km

Now for the direction, one vector is due north and the other is due east.

So the resultant vector is due north east.

So the final vector is 11√2 km due North-East.

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DIA [1.3K]

Answer:

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7 0
2 years ago
Read 2 more answers
If the train can slow down at a rate of 0.625 m/s2, how long, in seconds, does it take to come to a stop from this velocity?
qwelly [4]

Answer:

66.28 s

Explanation:

Step 1:

Acceleration,a=0.065m/s^2

Time,t=9.75 min=9.75\times 60=585s

1 min=60 s

Initial velocity,u=3.4m/s

We have to find the final velocity of train.

We know that

v=u+at

Substitute the values

v=3.4+0.065(585)=41.425m/s

Step 2:

Now, initial velocity,u=41.425m/s

Deceleration,a=-0.625m/s^2

Because the train velocity decreases

Final velocity, v=0

Again, substitute the values in the above formula

0-41.425=-0.625t

-41.425=-0.625t

t=\frac{-41.425}{-0.625}

t=66.28s

Hence, the train takes 66.28 s to come to stop from velocity 41.425m/s.

6 0
3 years ago
If anyone can answer these questions THEN U ARE A GENIUS
pantera1 [17]
1) C
2) 2[A]
3) 2[A]
4) a less bright (?)
b 1 [A]
c 1 [A]
5) brighter (?)
6)
a 0.8 (if it is the one on the right of 6)
b 0.4 [A]
c 0.4 [A]
d depends on where you place it.
7)
a place it next to X, right or left
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3 0
3 years ago
If a total of 1250 offspring were obtained from your cross, determine the number of offspring that you would expect to obtain th
irakobra [83]

Answer:

106 single crossover events

Explanation:

Total number of offspring = 1250

<u>Determine the number of offspring that would be expected </u>

( Rf between the genes vg and Pr ) * ( Total number of progeny )

  =   0.125 * 1250 ≈ 156 ( value for single and double crossovers )

next :

( value of the Rf of double crossovers ) * ( Total number of progeny )

= (0.322 * 0.125) = 0.04025  * 1250 = 50

Hence the number of offspring expected to obtain/represent a single crossover event between pr and vg

=  156 - 50 =  106

3 0
3 years ago
How much work must be done to stop an 1 800kg vehicle travelling at 30 m/s?
mars1129 [50]

Answer:

810 kJ

Explanation:

Work done is equal to change in kinetic energy

W=∆KE

Change in kinetic energy is given by

∆KE=½m(v²-u²)

Where ∆KE is the change in kinetic energy, m is mass of the vehicle, v is final velocity while u is initial velocity.

Since the vehicle must come to rest, the final velocity is zero.

Substituting 1800 kg for m, 0 m/s for v and 30 m/s for u then

∆KE=½*1800(0²-30²)=-810, 000J

Converted into kJ

∆KE=-810 kJ

Therefore, work done is 810 kJ

5 0
3 years ago
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