exists and is bounded for all
. We're told that
. Consider the interval [0, 3]. The mean value theorem says that there is some
such that
Since , we have
so 19 is the largest possible value.
If a point is om the prependicular bisector of a segm
1 answer:
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The answer choices tell you this is a parabola.
The given points tell you it opens upward and the vertex is (2, -3).
Your knowledge of the vertex form of the equation is the only "technology" that you need. The vertex form is
y = a(x - h)² + k . . . . . for vertex (h, k)
The fact that the y-value is 1 more than its vertex value when |x-2| = 1 tells you the scale factor "a" is 1.
You can write the model as
D. f(x) = (x -2)² - 3
The given points tell you it opens upward and the vertex is (2, -3).
Your knowledge of the vertex form of the equation is the only "technology" that you need. The vertex form is
y = a(x - h)² + k . . . . . for vertex (h, k)
The fact that the y-value is 1 more than its vertex value when |x-2| = 1 tells you the scale factor "a" is 1.
You can write the model as
D. f(x) = (x -2)² - 3
Answer:
The graph intersect the y-axis at (0,4.5)
The graph intersect the x-axis at (-3.6,0)
Step-by-step explanation:
The equation is;
-4y=-5x-18
Dived every term by -4
plot using a graph tool to view the liner graph as below
