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3 years ago

If a point is om the prependicular bisector of a segm

Mathematics

1 answer:

irina [24]3 years ago

5 0

Yes, that's a true statement. It's either a theorem or
a corollary to a theorem in elementary geometry.

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Someone please help with 4-6?

forsale [732]

4-6=-2 hope that helps!

5 0

3 years ago

Read 2 more answers

Select all the expressions that are equivalent to -36x+54y−90.

CaHeK987 [17]

Answer:

b) -18(2x -3y + 5)

d) 18(-2x + 3y - 5)

e) -2(18x - 27y + 45)

Step-by-step explanation:

a) -9( 4x - 6y - 10) = -36x + 54y + 90 not equal

b) -18(2x - 3y + 5) = -36x + 54y - 90 equal

c) -6(6x + 9y - 15) = -36x - 54y + 90 not equal

d) 18(-2x + 3y - 5) = -36x + 54y - 90 equal

e) -2(18x - 27y + 45) = -36x + 54y - 90 equal

f) 2(-18x + 54y - 90) = -36x + 108y - 180 not equal

7 0

2 years ago

Read 2 more answers

. can someone help pls

disa [49]

Answer:

The answer is 3,906.25

Step-by-step explanation:

All you have to do is divide 15,625 by 4! :)

6 0

2 years ago

There are 3 people pulling on an object, the first person pulls with a force of 226 newtons at a direction of 145 degrees the se

Alona [7]

Answer:

$R=883.74N$

Step-by-step explanation:

From the question we are told that:

Force 1 $F_1=226N$

Force 2 $F_2=331N$

Force 3 $F_3=377N$

Direction 1 $\theta_1=145 degrees \approx 35 \textdegree (2nd qudrant)$

Direction 2 $\theta_2=303 degrees \approx 57 \textdegree (3rd qudrant)$

Direction 3 $\theta_3=77 degrees$

Generally Resolving forces to X axis is mathematically given by

$\sum f_x=337cos77+331cos57+226sin35$

$\sum f_x=351.596N$

Generally Resolving forces to Y axis is mathematically given by

$\sum f_y=337sin77+331sin57+226cos35$

$\sum f_x=810.788N$

Generally the equation for Resultant force R is mathematically given by

$R=\sqrt{\sum f_x^2+\sum f_x^2}$

$R=\sqrt{351.596^2+810.788^2}$

$R=883.74N$

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2 years ago

List two school activities that u do in the morning time and afternoon time.write time for these two activities

zheka24 [161]

1. I complete some of my cyber: 7:00am to 10:00am

2. I spend time doing assignments in votech: 12:00pm to 2:30pm

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3 years ago

Read 2 more answers