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murzikaleks [220]

3 years ago

9

If a point is om the prependicular bisector of a segm

1 answer:

irina [24]3 years ago

5 0

Yes, that's a true statement. It's either a theorem or
a corollary to a theorem in elementary geometry.

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Can Somebody Please Help

Free_Kalibri [48]

Answer:

We have to put the data for purchased item in a frequency table.

Step-by-step explanation:

The diagram is attached below.

Firstly we have to see that how many customers fall under range $0 to 5$ .

Then $5 to 10$ .

Then $10 to 15$ .

Finally

$15 to 20$ .

If we go through the items purchased by customers we can see that item ranges from $0 to 5$ have $4$ customers.

Item purchased range from $5 to 10$ have $2$ customers.

Item purchased range from $10 to 15$ have $7$ customers.

Item purchased range from $15 to 20$ have $1$ customers.

Total number of customers = $14$

As we have total $14$ number of customers and they have varied quantity of items purchased.

6 0

3 years ago

Plz plz plz help fast it’s graded

Paraphin [41]

Answer: 117 degrees

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is -2 22/25 as a decimal?

adelina 88 [10]

Answer:

-2 22/25 = -72/25

= -2.88

8 0

3 years ago

Read 2 more answers

QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is

soldi70 [24.7K]

Answer:

$PQR = 20$

Step-by-step explanation:

Given

Bisector: QS

$PQS = 5x$

$RQS = 2x + 6$

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

$PQS = RQS$

Substitute expressions for PQS and RQS

$5x = 2x + 6$

Collect Like Terms

$5x - 2x = 6$

$3x = 6$

Divide both sides by 3

$x = 2$

Solving for PQR;

$PQR = PQS + RQS$

$PQR = 5x + 2x + 6$

$PQR = 7x + 6$

Substitute 2 for x

$PQR = 7 * 2 + 6$

$PQR = 14 + 6$

$PQR = 20$

4 0

3 years ago

3(Y-4) - 2(y-9) + 5(y+6)=0

kumpel [21]

Answer: Y = -y - 12

Step-by-step explanation:

4 0

3 years ago