Because triangle QSR is isosceles ∠SQR=∠SRQ=35°. The sum of the angles in a triangle is 180°, so ∠QSR=180°-35°-35°=110°. The measure of a straight line is 180°, so ∠PSQ=180°-110°=70°. Because triangle PSQ is also isosceles ∠PSQ=∠PQS=70°. Then, ∠QPS=180°-70°-70°=40°.
Answer: p = 30 q = 30 (if not touching edge of hexagon but if it is touching edge one of the pairs) then p or q = 120 and p and q = 30
Step 1) Sum of an interior angle of a polygon = 720 degree where n = 6 as 6 exterior sides = (n-2) * 180 = (6-2) * 180 = 4 * 180 = 720 degree Where the measure of each angle of a hexagon = 720/ 6 = 120 degree Step 2) Then show 3 angle letter names = 180 degree Step 3) Angle name letters + 2 angle (other two names letters inside within triangle) add up to 180 degree Step 3) State since triangle name (of all letters within one triangle) is Isosceles Step 4) <u>Triangle (state same triangle letters with number 2 in front) = 180 - 120 = 60 then state triangle (letter name) / 2 = 30 degrees </u>obviously the 120 and 60 differentiates if not a hexagon to a pentagon if not a hexagon = (3 *180) / 5 = 108 then due to isosceles (180 - 108)/ 2 = 72/2 = 36 degree for a p<u>entagon </u>or 30 degree each for p + q for a <u>hexagon</u> etc
