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juin [17]
3 years ago
9

Simon neatly arranged 35 radio controlled cars in 5 rows on the shelf find the number of cars placed in each row

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:

7

Step-by-step explanation:

The shelf has got 5 rows and the total number of cars is 35. We have to find the amount of car in each row.

Since there is no any other condition for the number of cars in rows (for example, it could be given that the number of cars in rows is different from each-other) we have to find the exact and the same number. Also, we bear in mind that the number of the cars has to be a full number.

The solution is 35 : 5 = 7 cars

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Estimate of 2,854x9 help me find it and you’ll get ten points
iVinArrow [24]
The answer to this question is 25,686
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3 years ago
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Jada is putting a border around her rectangular garden. The garden is 12.63 meters long and 3.28 meters wide. Compare the estima
alisha [4.7K]

Answer:

Part A: C

Part B: B

Part C: 15.91

Step-by-step explanation:

first round the 2 numbers by the tenths. Then round the numbers by ones(whohle number). After that, since ther are four sides we do 12.63 + 3.28 + 12.63 + 3.28 which equals to 15.91.

8 0
3 years ago
Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what
professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 64, \sigma = 1.5

What percentage of women are between 65.5 inches and 68.5 inches?

This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.

X = 68.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.5 - 64}{1.5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 65.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{65.5 - 64}{1.5}

Z = 1

Z = 1 has a pvalue of 0.8413

So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.

8 0
3 years ago
Breakfast at Denny's cost $8.63. You give a 15% tip. What is the total cost?
Nataliya [291]

Answer:

9.92

Step-by-step explanation:

8.63 x 1.15=9.92

3 0
3 years ago
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]
masha68 [24]
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]  \\ 25-[2+5y-3y-6]=-6y+15-[5y-5-3y+3] \\ 25-2-5y+3y+6=-6y+15-5y+5+3y-3 \\ -2y+29=-8y+17 \\ 6y+29=17 \\ 6y=-12 \\ y=-2
Hope this helped :)
6 0
3 years ago
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