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3 years ago

What is the ratio of the corresponding sides of ABCD to LMNO? 3/2 1/2 2/3 2/1

Mathematics

1 answer:

kompoz [17]3 years ago

4 0

Answer:

2 : 3

Step-by-step explanation:

Calculate the ratio of corresponding sides

AB : LM = 4 : 6 = 2 : 3

AD : LO = 2 : 3

DC : ON = 4 : 6 = 2 : 3

CB : NM = 2 : 3

The ratio of corresponding sides is 2 : 3

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Kruka [31]

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

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x = 2

y = 2^2 -4×2 = 4-8 = -4

x=3

y = 3^2 - 4×3 = 9-12 = -3

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y = 2x^2 + x

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x = 1

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3 years ago

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3 years ago

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Using Substitution solve: y=x+5<br> 4x+y=20

Vladimir [108]

Answer:

Step-by-step explanation:

So first, plugin y to your equation, it should look like this: 4x+x+5+20. Now, we can solve this. Next, we have two x's so we can combine them. The equation will now look like this: 5x+5=20. Now, we have an extra 5 laying around that we need to get rid of, so we can subtract that 5 to both sides of the equation and we get this: 5x-5=20-5 which ends up being 5x=15. Now, we just divide both ides by 5 and since 15 divided by 5 is 3, we get: x=3

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3 years ago

Need help can anyone help me???

Paladinen [302]

Answer:

it is greater than 45°

Step-by-step explanation:

From the relationship of angles and secants/tangents, we have ...

m∠GSO = (long arc GO -arc GT)/2

Solving for (long arc GO), we have ...

2(m∠GSO) +arc GT = (long arc GO)

We know that (long arc GO) > 180°, so we can write ...

2(m∠GSO) +90° > 180° . . . . arc GT = 90°

2(m∠GSO) > 90° . . . . . . subtract 90°

m∠GSO > 45° . . . . . . . . divide by 2

_____

<em>Alternate solution</em>

Inscribed ∠GOT has half the measure of arc GT, so is 45°.

You know that if angle G were 90°, then the right triangle would be isosceles, and angle S would also be 45°. In this triangle, arc GTO is less than 180°, so angle G is less than 90°.

When angle G gets smaller, the sum of angles remains the same, so angle S must be larger than 45°.

This reasoning is written more formally in the math above.

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