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2 years ago

Using Substitution solve: y=x+5 4x+y=20

Mathematics

1 answer:

Vladimir [108]2 years ago

4 0

Answer:

Step-by-step explanation:

So first, plugin y to your equation, it should look like this: 4x+x+5+20. Now, we can solve this. Next, we have two x's so we can combine them. The equation will now look like this: 5x+5=20. Now, we have an extra 5 laying around that we need to get rid of, so we can subtract that 5 to both sides of the equation and we get this: 5x-5=20-5 which ends up being 5x=15. Now, we just divide both ides by 5 and since 15 divided by 5 is 3, we get: x=3

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denis-greek [22]

$4.07 × 9.6= $39.072 or $39.07; $20 × 2= $40; 40 - 39.07= 0.93.
The answer is $0.93.

Hope this helps :)

6 0

2 years ago

35 + 70 = 35(1 + 2)<br> O Yes<br> O No

Sliva [168]

Answer:

Yes

Step-by-step explanation:

Because 35 * 1 is 35 and 35 * 2 is 70

6 0

3 years ago

Read 2 more answers

Plz help me with the ones that are circled

Alisiya [41]

Your answer for your question is going to be.... um.... sorry I forgot

3 0

2 years ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

2 years ago

In the field of quality control, the science of statistics is often used to determine if a process is "out of control." Suppo

Usimov [2.4K]

Answer:

a) P=0.0225

b) P=0.057375

Step-by-step explanation:

From exercise we have that 15% of items produced are defective, we conclude that probabiity:

P=15/100

P=0.15

a) We calculate the probabiity that two items are defective:

P= 0.15 · 0.15

P=0.0225

b) We calculate the probabiity that two of three items are defective:

P={3}_C_{2} · 0.85 · 0.15 · 0.15

P=\frac{3!}{2!(3-2)!} · 0.019125

P=3 · 0.019125

P=0.057375

6 0

2 years ago