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kirill [66]
3 years ago
6

Can someone please give me the awnsers !!!!!!

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

I'll do the left side.

1:

-6=\frac{n}{3}  -8 \\2 = \frac{n}{3} \\n = 6

Inverses are your friends, for example to get n - 3 = 0 where n is on one side, do the inverse of subtraction ( addition) so you get n - 3 + 3 = 3 \\\\n = 3

-7 = \frac{n}{4} - 3 \\-4 = \frac{n}{4}\\n = -16

-13 = 5y + 7 \\-6 = 5y \\

On "y" there is a <em>coefficient </em>of 5, aka 5*y,  the inverse of multiplication is division

\frac{-6}{5} = y

-6 + \frac{x}{2} = -3\\ \frac{x}{2} = 3 \\x = 6

You finish the rest, but you gotta remember this, isolate the variable (x, y, z, whatever) by doing inverses

inverses

addition - subtraction

multiplication - division

<em>Everything in math builds on this!!!</em>

<em></em>

<h3 />

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3 years ago
Given that SQ¯¯¯¯¯ bisects ∠PSR and ∠SPQ≅∠SRQ, which of the following proves that PS¯¯¯¯¯≅SR¯¯¯¯¯?
yanalaym [24]

Step-by-step explanation:

It is given that ∠SPQ≅∠SRQ

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles S P Q and S R Q are highlighted in red.

It is also given that SQ⎯⎯⎯⎯⎯

bisects ∠PSR

.

By the definition of angle bisector, ∠PSQ≅∠QSR

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are congruent and highlighted in red.

△PQS

and △RQS share a common side SQ⎯⎯⎯⎯⎯, and SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

by the Reflexive Property of Congruence.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Segment S Q is highlighted in red.

Two angles, ∠SPQ

and ∠PSQ, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △PQS are congruent to two angles, ∠SRQ and ∠QSR, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △RQS

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are highlighted in red. Angles S P Q and S R Q are highlighted in red. Side S Q is highlighted in blue.

So, △PQS≅△RQS

by the Angle-Angle-Side (AAS) Congruence Theorem.

PS⎯⎯⎯⎯⎯

and SR⎯⎯⎯⎯⎯ are corresponding sides of congruent triangles, △PQS and △RQS. So, PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

by CPCTC.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Sides S R and S P are congruent and highlighted in red.

Translate these six statements and reasons into a 2

-column proof,

1. ∠SPQ≅∠SRQ

(Given)

2. SQ⎯⎯⎯⎯⎯

bisects ∠PSR

. (Given)

3. ∠PSQ≅∠QSR

(Def. of ∠

bisect)

4. SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

(Reflex. Prop. of ≅

)

5. △PQS≅△RQS

(AAS Steps 1, 3, 4)

6. PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

(CPCTC)

There you go

4 0
3 years ago
Angle T had a measure between 0 and 360 and is coterminal with -170 angle. What is the measure of angle T?
Alika [10]

Answer: The answer is 190°.


Step-by-step explanation: We are to find the measure of ∠T which lies between 0° and 360° and is co-terminal with an angle of measure -170°.

We know that two angles are said to be co-terminal if one is obtained from the other by either adding or subtracting 360°.

So, angles which are co-terminal with -170° are

-170° + 360° = 190°,  -170° - 360° = 530°, etc.

Since 190° lies between 0° and 360°, so measure of ∠T is 190°.

Thus, the answer is 190°.


5 0
3 years ago
What number should be added to the expression x^2+2x to change it into a perfect square trinomial?
sweet [91]
To make x^2 + 2x a perfect square we need to add the term { 2 / (2*1) }^2

which equals 1.

Add 1 to both sides: x^2 + 2x = 8

add 1 to both sides: x^2 + 2x + 1 = 8 + 1 (x + 1)^2 = 9

Take square root on both sides: x + 1 = +/- 3 x = +3 - 1 or x = -3 - 1 x = 2 or x = -4
6 0
3 years ago
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