Answer:
BY increasing pressure and decreasing temperature.
Explanation:
- The solubility of a gas increases with decrease in the temperature.
- Also the solubility of a gas increases with increasing pressure.
- A gas can be compressed by increasing the pressure and decreasing the temperature.
- FOR example the gas in domestic LPG cylinders are in compressed form inside the cylinder.
- A gas takes the form of a liquid after compressing. Whenever it comes back to normal temperature and pressure it takes back to its gaseous form back.
The gaseous oxygen is water soluble and does not react with it
O2 + 2H2O + 4 e= 4 OH-
Answer:
A. To be precise, it must be able to make measurements repeatedly over a long period of time.
Explanation:
The precision of a scientific measuring tool can be defined as how close the values between multiple measurements are to each other, when repeated under the same conditions.
This ultimately implies that, the precision of a scientific measuring tool reflects the reproducibility and repeatability of its measurements, irrespective of how accurate the measurements are.
In science, one of the most effective ways to determine the precision of a scientific measuring tool is to find the difference between the highest and lowest measurements (measured values).
Hence, the statement which correctly describes a characteristic that a scientific measuring tool should have is that, to be precise, it must be able to make measurements repeatedly over a long period of time.
Answer: Option (b) is the correct answer.
Explanation:
When it rains, then mud in the backyards become wet. It is known that earthworms live inside earth and diffusion of oxygen gets slower through water than through air.
As a result, supply of oxygen to the worms decreases in wet mud hence, they come to the surface in order to breathe.
Thus, we can conclude that wet mud in the backyard most likely formed the earthworms.
<span>To determine the pH of the solution given, we make
use of the acid equilibrium constant (Ka) given. It is the ratio of the
equilibrium concentrations of the dissociated ions and the acid. The
dissociation reaction of the CH3COOH acid would be as follows:
</span>CH3COOH = CH3COO- + H+<span>
The acid equilibrum constant would be expressed as follows:
Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5
<span>
To determine the equilibrium concentrations we use the ICE table,
CH3COOH H+ </span>CH3COO<span>-
I 1.60 0 0
C -x +x +x
----------------------------------------------------------------
E 1.60-x x x
</span>1.8× 10^–5 = [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>
Solving for x,
x = 1.69x10^-3 = [H+] = [F-]
pH = -log [H+] = -log [1.69x10^-3] = 2.8
