Answer:
Therefore,
The potential (in V) near its surface is 186.13 Volt.
Explanation:
Given:
Diameter of sphere,
d= 0.29 cm
Charge ,
To Find:
Electric potential , V = ?
Solution:
Electric Potential at point surface is given as,
Where,
V= Electric potential,
ε0 = permeability free space = 8.85 × 10–12 F/m
Q = Charge
r = Radius
Substituting the values we get
Therefore,
The potential (in V) near its surface is 186.13 Volt.
Light waves are never 'aborted'.
They can be 'absorbed', and I think that's what you mean.
It's what happens when light hits something or goes into it,
and never comes out.
"Absorb" just means "soak up". When a light wave hits something and
gets soaked up in it, it's gone, and never comes out the other side.
The light wave certainly gets changed ... it no longer exists.
The object that absorbs it also gets changed. It soaks up the energy
in the light wave, and it has a little more internal energy (heat) than it
had before the light hit it.
2 seconds is the period (time it takes to complete one cycle)
The sun. The more mass an object has, the greater gravitational pull it will have, as mass attracts other mass.
Circular motion occurs when an object travels in a curved path.
