Answer:
The frequency of the second harmonic (
) is 11.97 Hz.
Explanation:
Given;
mass of the string, m = 25 g = 0.025kg
tension on the string, T = 43 N
length of the string, L = 12 m
The speed of wave on the string is given as;

where;
μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m

The wavelength of the first harmonic wave is given as;

The frequency of the first harmonic is given as;

The wavelength of the second harmonic wave is given as;

The frequency of the second harmonic is given as;

Therefore, the frequency of the second harmonic (
) is 11.97 Hz.
We are given the acceleration of the bus as a function of time:
a(t) = 1.2t
Let the velocity also be a function of time v(t).
Since a(t) is the change of v(t) over time, we can use the fundamental theorem of calculus to determine the velocity at t = 2s, or v(2), given that:
a(t) = 1.2t
v(1) = 5
v(2) - v(1) = 
v(2) - 5 = 
v(2) - 5 = 0.6t² evaluated between t = 1 and t = 2
v(2) - 5 = 0.6(4) - 0.6(1)
v(2) = 1.8 + 5
v(2) = 6.8m/s
Explanation:
may I ask what it is on because I might be able to help out
Particles in the solar nebula were more spread out at greater distances, so that accretion took longer and there was less time to pull in gas before the solar wind cleared the nebula.
The kinetic energy of plane is 10285000 J
Kinetic energy is defined as the energy possed by an object in motion. The mathematical representation of kinetic energy is given below:
<h3>KE = ½mv²</h3>
Where:
KE is the kinetic energy
m is the mass of the object
v is the velocity of the object.
With the above formula, we can obtain kinetic energy of the plane as follow:
Mass (m) = 6800 kg
Velocity (v) = 55.0 m/s
<h3>Kinetic energy (KE) =? </h3>
KE = ½mv²
KE = ½ × 6800 × 55²
KE = 3400 × 3025
<h3>KE = 10285000 J</h3>
Therefore, the kinetic energy of plane is 10285000 J
Learn more: brainly.com/question/24713075