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3 years ago

Is the appearance of a light wave changed as it is aborted?

1 answer:

7 0

Light waves are never 'aborted'.

They can be 'absorbed', and I think that's what you mean.
It's what happens when light hits something or goes into it,
and never comes out.

"Absorb" just means "soak up". When a light wave hits something and
gets soaked up in it, it's gone, and never comes out the other side.

The light wave certainly gets changed ... it no longer exists.

The object that absorbs it also gets changed. It soaks up the energy
in the light wave, and it has a little more internal energy (heat) than it
had before the light hit it.

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Starting from the front door of your ranch house, you walk 50.0 m due east to your windmill, and then you turn around and slowly

Hunter-Best [27]

Answer:

Average velocity

$v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}$

Average speed,

$S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}$

Explanation:

(a)Average velocity

We have to find the average velocity. We know that velocity is defined as the rate of change of displacement with respect to time.

To find the average velocity we have to find the total displacement.

since displacement along east direction is 50m

and displacement along west=40m

so total displacement,

$d=50m-40m\\d=10m$

total time,

$t=28 s+42 s\\t=70 s$

therefore, average velocity

$v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}$

(b)Average Speed:

Average speed is defined as the ratio of total distance to the total time

it means

Average speed= total distance/total time

here total distance,

$D= 50m+40m\\D=90m$

and total time,

$t= 28s+40s\\t=70s$

therefore,

Average speed,

$S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}$

8 0

3 years ago

Calculate the kinetic energy of running kitten that has a mass of 4 kg and velocities of 2 m/s

Helga [31]

The equation you use is Ke = 1/2mv^2. when you plug in the numbers that are given you get Ke= 1/2(4)(2^2) which gives you a Kinetic Energy of 8

5 0

3 years ago

How do scientists measure the amount of carbon dioxide in the atmosphere for dates prior to the 1955?

Debora [2.8K]

The scientists measured the amount of carbon dioxide in the atmosphere for dates prior to 1955, From air bubbles in glacial ice cores.

Almost 412 parts per million (ppm) of carbon dioxide are currently present in the Earth's atmosphere, and that number is increasing. This indicates an 11 per cent increase since 2000, when the concentration was close to 370 ppm, and a 47 per cent increase since the start of the Industrial Age when the concentration was close to 280 ppm. Most of the time, scientists do not consider Carbon dioxide as a percentage of the earth's atmosphere. It helps to picture a million equal pieces of an atmospheric gas sample.

Learn more about carbon dioxide here:

brainly.com/question/3049557

#SPJ4

6 0

1 year ago

A 650 × 10–4 F capacitor stores 24 × 10–3 of charge. What is the potential difference between the plates?

olasank [31]

Answer:

0.369 V

<u>Explanation:</u>

Given :

Capacitance ( c ) = 650 × 10–4 F

Charge ( q ) = 24 × 10–3 C

We are asked to find potential difference ( v )!

We know:

q = c v

= > v = q / c

Putting values here we get:

= > v = ( 24 × 10–3 ) / ( 650 × 10–4 ) V

= > v = 240 / 650 V

= > v = 24 / 65 V

= > v = 0.369 V

Therefore, potential difference between the plates is 0.369 V

8 0

3 years ago

A 3000 kg deck is cantilevered over a beam as shown. It is attached to the house at the other end. Find the force of the beam.

Afina-wow [57]

The beam is acting as the pivot and the weight of the deck acts through its center its gravity, at the midpoint of the deck.
Center of gravity at: (16 + 4)/2 = 10 ft

Converting 4 ft to meters: 1.22 m
Converting 10 ft to meters: 3.05

F x 1.22 = 3.05 x 3000 x 9.81
F = 73,600 N

4 0

3 years ago