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antoniya [11.8K]
2 years ago
14

A race car has a velocity of 382 km/h to the right. If the car’s mass is 705 kg and the driver’s mass is 65 kg, what force is ne

eded to bring the car and driver to a stop in 12.0 s? What is the car’s stopping distance?
Physics
1 answer:
Lady bird [3.3K]2 years ago
6 0

Answer:

Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12

Required: Δx

F = Δp / Δt

  = \frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]

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<h3>How to convert 90849.84 cm³/min to cm³/s</h3>

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90849.84 cm³/min = 1514.164 cm³/s

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24 gallon/min = 1514.164 cm³/s

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