One form of the equation of a parabola is
y = ax² + bx + c
The curve passes through (0,-6), (-1,-12) and (3,0). Therefore
c = - 6 (1)
a - b + c = -12 (2)
9a + 3b + c = 0 (3)
Substitute (1) into (2) and into (3).
a - b -6 = -12
a - b = -6 (4)
9a + 3b - 6 = 0
9a + 3b = 6 (5)
Substitute a = b - 6 from (4) into (5).
9(b - 6) + 3b = 6
12b - 54 = 6
12b = 60
b = 5
a = b - 6 = -1
The equation is
y = -x² + 5x - 6
Let us use completing the square to write the equation in standard form for a parabola.
y = -[x² - 5x] - 6
= -[ (x - 2.5)² - 2.5²] - 6
= -(x - 2.5)² + 6.25 - 6
y = -(x - 2.5)² + 0.25
This is the standdard form of the equation for the parabola.
The vertex us at (2.5, 0.25).
The axis of symmetry is x = 2.5
Because the leading coefficient is -1 (negative), the curve opens downward.
The graph is shown below.
Answer: y = -(x - 2.5)² + 0.25
Impossible.
The reason is because there is no way you will get a '7' on a die that is marked 1 - 6. There is no 7.
Hey YO! Try the websire CALCULATOR SOUP PRIME FACTORISATION. MARK ME AS BRAINLIST
Dam I forgot :/ wha it was
9514 1404 393
Answer:
f(x)=0
Step-by-step explanation:
For the function to be both even and odd, you must have ...
f(-x) = f(x) = -f(-x)
Adding f(-x) we have ...
2f(-x) = 0
Then dividing by 2 and recognizing f(-x) = f(x), we have ...
f(-x) = f(x) = 0