$x^2-12x+36\\Break\:the\:expression\:into\:groups\\=\left(x^2-6x\right)+\left(-6x+36\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-6x\mathrm{:\quad }x\left(x-6\right)\\\mathrm{Factor\:out\:}-6\mathrm{\:from\:}-6x+36\mathrm{:\quad }-6\left(x-6\right)\\=x\left(x-6\right)-6\left(x-6\right)\\\mathrm{Factor\:out\:common\:term\:}\left(x-6\right)\\=\left(x-6\right)\left(x-6\right)\\Refine\\Answer: \left(x-6\right)^2$

7 0

3 years ago

I need help asap with this question it’s due tonight

Vilka [71]

Answer:

The answer is 44 cm^2

I hope it helps

3 0

2 years ago

Read 2 more answers

F m∠A = 110 degrees and m∠B = 35 degrees, find m∠1.

NISA [10]

I think M<1 will equal 35 degrees.

5 0

2 years ago

State whether the given measurements determine zero, one, or two triangles.

Lady bird [3.3K]

I bet you're doing the Law of Sines right now. If you use the law of sines you find out that angle A is a 90 degree angle. There is only one triangle you can make with these measurements because if you have one angle of 30 and another of 90, the 3rd angle has to be a 60 degree angle. So it is a special right triangle, 30-60-90

8 0

2 years ago