The correct answer is 'Equation F can be written as 2d + 1 = 3d + 7'. In order to find the answer to a system of equations, the two equations must be set equal to each other. For instance, if we had the equations x = y + 1 and x = 3y - 1, we would set the two equations equal to one another to find the answer.
x = y + 1
x = 3y - 1
y + 1 = 3y - 1
1 = 2y - 1
2 = 2y
1 = y
x = y + 1
x = 1 + 1
<span>x = 2
We can use this to solve the set of equations above.
</span><span>2d + 1 = 3d + 7
</span>1 = d + 7
-6 = d
c = 2d + 1
c = 2(-6) + 1
c = -12 + 1
c = -11
Hope this helps!
Answer:
1/3
Step-by-step explanation:
Probability of solving ten problems by Carl
Given
Total number of problems = 20
Number of problems studied by Carl = 15
Number of problems out of the 20 set of problem coming in test is 10
Case I - All ten problems come from the set of known 15 question
10/15 * 10/20 = 1/3
V of w sphere =
r³
Multiply by 3 on either sides to get rid of the fraction.
3V = 4
r³
Now divide either sides by 4
to isolate r³
r³
4
and 4
cancels out
= r³
Take the cube root to isolate r.
![\sqrt[3]{ \frac{3V}{4 \pi } } = \sqrt[3]{r^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20%3D%20%20%5Csqrt%5B3%5D%7Br%5E3%7D%20)
the cube root cancels the cube
![\sqrt[3]{ \frac{3V}{4 \pi } }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20)
= r
5/6 x = 30
x = 30 ÷ 5/6
x = 36 <=== muffins you start with
Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
