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ruslelena [56]
4 years ago
11

Help me please !!!

Mathematics
1 answer:
Nat2105 [25]4 years ago
6 0

Answer:

For 3x^2+4x+4=0

Discriminant= = -32

The solutions are

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= -44

The solutions

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= -36

The solutions

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a= (1-√-1)/3

Step-by-step explanation:

Formula for the discriminant = b²-4ac

let the discriminant be = x for the equations

The solution of the equations

= (-b+√x)/2a and = (-b-√x)/2a

For 3x^2+4x+4=0

Discriminant= 4²-4(3)(4)

Discriminant= 16-48

Discriminant= = -32

The solutions

(-b+√x)/2a =( -4+√-32)/6

(-b+√x)/2a= (-4 +4√-2)/6

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a =( -4-√-32)/6

(-b-√x)/2a= (-4 -4√-2)/6

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= 2²-4(3)(4)

Discriminant= 4-48

Discriminant= -44

The solutions

(-b+√x)/2a =( -2+√-44)/6

(-b+√x)/2a= (-2 +2√-11)/6

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a =( -2-√-44)/6

(-b-√x)/2a= (-2 -2√-11)/6

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= (-6)²-4(9)(2)

Discriminant= 36 -72

Discriminant= -36

The solutions

(-b+√x)/2a =( 6+√-36)/18

(-b+√x)/2a= (6 +6√-1)/18

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a =( 6-√-36)/18

(-b-√x)/2a= (6 -6√-1)/18

(-b-√x)/2a= (1-√-1)/3

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Answer:

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We can subtract 4r by r, and that gives 3r. 3 subtracted by negative 3 gives 6 (Remember, 2 negatives is a positive!). This gives 3r+6

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Answer:

The motorist's average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.

Step-by-step explanation:

Let the motorist's average rate in the afternoon = <em>x</em> mph.

It is given that his average rate in the morning was twice his average rate in the afternoon.

Therefore, his average rate in the morning = 2<em>x</em> mph.

Let <em>t</em> be the time taken for the morning trip.

It is given that he spent 5 hours for driving.

So, the time taken by him for the afternoon trip = 5 - <em>t</em>.

Now, using the formumla, speed=\frac{distance}{time},

the verbal model for the morning trip is:

2x=\frac{150}{t}

<em>xt</em> = 75

The verbal model for the afternoon trip is:

x=\frac{50}{5-t}

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Substituting <em>xt</em> = 75, we get,

5<em>x</em> - 75 = 50

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