-3x+10y=-60 3x+5y=15

#9 was the the one I need help with anyone plz help Thank You:)

pentagon [3]

Your answers are wrong. the function f(x) is like a factory. you put in something ( a number) and it will spit you out something else (a different number depending on the function). your function, f (x)= -2x+1

you can put anything in that function. let say k.
f(x=k) = -2k+1. you just replace the x with k.
in this particular problem they way f(-2) ,f(0), f(1) and f(2).
here are the results
f(x=-2) = f(-2) = -2×(-2)+1 =5
f(x=0) = f(0) = -2×(0)+1 =1
f(x=1) = f(1) = -2×(1)+1 =-1
f(x=2) = f(2) = -2×(2)+1 =-3

3 0

3 years ago

Patrick wanted to gather data about the cost of joining a community pool in his area. He plotted the data and determined that th

ohaa [14]

Answer:

The y-intercept is 40. This is the cost of registration ⇒ last answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Patrick wanted to gather data about the cost of joining a community

pool in his area

- He plotted the data and determined that the average community

pool membership cost consists of a one-time registration fee and

a monthly fee

∴ The cost consists of two parts:

# Part A: one-time registration fee, it is a fixed amount not depend on

any other condition

# Part B: monthly fee, it depends on the number of months

- He modeled that by the equation y = 15 x + 40, where

# y is the cost for the membership

# 15 is the monthly fee

# x is the number of months

# 40 is the one-time registration

- The form of the equation is y = mx + c, where c is the y-intercept

∴ The y-intercept in the equation y = 15 x + 40 is 40

∴ The y-intercept is the one-time registration fee

* The y-intercept is 40. This is the cost of registration

4 0

3 years ago

Geometry Special Quadrilaterals show work please

Charra [1.4K]

Answer:

a = 16

w = 125

x = 120

y = 55

Step-by-step explanation:

FINDING 'a'

31 = a + 46 / 2

62 = a + 46

16 = a

FINDING 'w'

* This section looks Non-Isosceles trapezoid so I will be following the rule according it

w + 55 = 180

w = 125

FINDING 'y'

y = 55

- Because of corresponding angles

FINDING 'x'

* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.

x + 60 = 180

x = 120

Hope this helped ^^

(Please inform me of any mistakes or misunderstandings!)

6 0

3 years ago

2. Evaluate each function at the specific value

Oliga [24]

F(6) says “take f(x) = -4x + 11 and put 6 in for every x-value and then clean it up.”

f(6) = -4(6) + 11

      = -24 + 11

      = -13

f(x) = -1 says “set your function equal to -1 and solve for x”

    f(x) = -1

-4x+11 = -1

-4x = -12

        x = 3

So f(3) = -1.

8 0

3 years ago

Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an

Fantom [35]

9514 1404 393

Answer:

about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

Additional comments

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

__

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.

3 0

3 years ago