While linear<span> equations are always straight, </span>nonlinear<span> equations often feature curves.</span>
<h2>
Dionne will fold 210 packing boxes in "60 mìnutes" and</h2><h2>
Elias will fold 210 packing boxes in "70 mìnutes".</h2>
Step-by-step explanation:
Given,
Dionne can fold 175 packing boxes = 50 mìnute and
Elias can fold 120 packing boxes = 40 minutes
To find, the total time each person to fold 210 packing boxes = ?
∵ Dionne can fold 175 packing boxes = 50 mìnute
∴ In 1 mìnute, Dionne can fold number of packing boxes = 
= 3.5
∴ Dionne can fold 210 packing boxes = 
minutes
= 60 minutes
Also,
Elias can fold 120 packing boxes = 40 minutes
∴ In 1 mìnute, Elias can fold number of packing boxes = 
= 3
∴ Elias can fold 210 packing boxes = 
minutes
= 70 minutes
Thus, Dionne will fold 210 packing boxes in "60 mìnutes" and
Elias will fold 210 packing boxes in "70 mìnutes".
We can find this using the formula: L= ∫√1+ (y')² dx
First we want to solve for y by taking the 1/2 power of both sides:
y=(4(x+1)³)^1/2
y=2(x+1)^3/2
Now, we can take the derivative using the chain rule:
y'=3(x+1)^1/2
We can then square this, so it can be plugged directly into the formula:
(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9
We can then plug this into the formula:
L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765
The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
Answer:
...
Step-by-step explanation:
