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STALIN [3.7K]
3 years ago
13

Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.† Suppose a small group of 20 Allen's hummingb

irds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with = 0.34 gram.
(a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.)
lower limit=
upper limit =
margin of error =

(b) What conditions are necessary for your calculations? (Select all that apply.)
a.uniform distribution of weights
b.normal distribution of weights
c.n is large
d. is unknown
e. is known


(c) Interpret your results in the context of this problem.
a. We are 80% confident that the true average weight of Allen's hummingbirds falls within this interval.
b.The probability that this interval contains the true average weight of Allen's hummingbirds is 0.80.
c.We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval.
d.The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20.

(d) Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.12 for the mean weights of the hummingbirds. (Round up to the nearest whole number.)
________ hummingbirds
Mathematics
1 answer:
mixas84 [53]3 years ago
4 0
This is 5 point higher the points and maybe people will do it looks like a lot
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Solutions for 2x^2+18x=20, worth a TON, please only 100% answers ! Thank u !
victus00 [196]

Answer:

The solution of the given quadratic equation is 1 and (-10).

Step-by-step explanation:

2x^2+18x=20

x^2+9x=\frac{20}{2}

x^2+9x-10=0

ax^2+bx+c=0

Solving equation by quadratic formula:

Here , a = 1,b = 9, c = (-10)

D=b^2-4ac=(9)^2-4(1)(-10)=121

x=\frac{-b+{\sqrt{D}}}{2a}=\frac{(-9)+\sqrt{121}}{2(1)}=1

x=\frac{-b-{\sqrt{D}}}{2a}=\frac{(-9)-\sqrt{121}}{2(1)}=(-10)

The solution of the given quadratic equation is 1 and (-10).

5 0
3 years ago
Kristin paid $18.60 for 3 pounds of candy.
zvonat [6]

Answer:

$6.20 is the cost of candy per pound.

5/31 lbs of candy would be for $1.

Step-by-step explanation:

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4 years ago
The price of a car increased by 7% which expression can be used to calculate the new price of the car
julsineya [31]

Answer: P * ( 1 + 7%)

Step-by-step explanation:

You included no options but the expression should go something like this:

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Where Pn is the new price

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Evaluate the expression 4⋅f(6)−6⋅g(5)
sladkih [1.3K]

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send full question

Step-by-step explanation:

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3 years ago
Using triangle A B C as the pre-image and the origin as the center of dilation, which coordinate point is not a coordinate of a
Ostrovityanka [42]

Answer:

The correct option is:

begin ordered pair 4 comma 12 end ordered pair i.e. (4,12).

Step-by-step explanation:

We are given the coordinates of the point A,B and C of the triangle ΔABC as:

A(-1,3) , B(2,1) and C(-2,-1).

Now it is given that there is dilation of this triangle about the origin with a scale factor of 4.

This means that the change in the coordinates after the transformation is given by the rule:

(x,y) → (4x,4y)

As A → A' , B → B' and C → C'

Hence the coordinates A',B' and C' are given by:

A' are (4×-1,4×3)=(-4,12)

B' are (4×2,4×1)=(8,4)

and C' are (4×-2,4×-1)=(-8,-4).

<em>Hence the coordinate point which is not a coordinate of dilation is:</em>

<em>begin ordered pair 4 comma 12 end ordered pair  i.e. (4,12)</em>

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3 years ago
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