now, let's recall the rational root test, check your textbook on it.
so p = 18 and q = 1
so all possible roots will come from the factors of ±p/q
now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.
recall that, a root will give us a remainder of 0.
let us use +3.
well, that one worked... now, using the rational root test, our p = 6, q = 1.
so the factors from ±p/q are ±3, ±2, ±1
let's use 3 again
and of course, we can factor x²-x-2 to (x-2)(x+1).
(x-3)(x-3)(x-2)(x+1).
Answer:No
Step-by-step explanation:
Try y-2=-2(x-5) that should work if not the slope intercept form is y=-2x+12
Answer:
A)
Step-by-step explanation:
from 0 to 5, x was moved right 5 units on the first is + 5
then, -1 to -5. it went down 4 units so -4
Answer:
Step-by-step explanation:
<u>Multiply and simplify:</u>
- (x - 1)(x + 2)(x + 3) =
- (x² + 2x - x -2)(x + 3) =
- (x² + x - 2)(x + 3) =
- x³ + 3x² + x² + 3x - 2x - 6 =
- x³ + 4x² + x - 6
<u>From the final polynomial we can see that:</u>
- a = 1, b = 4, c = 1 and d = - 6
So all the coefficients are positive but the constant d is negative