Fahrenholz's rule is supported when: comparison of phylogenies for host and parasite show a correlated pattern of evolution
<h3>What is Fahrenholz's rule ?</h3>
The close correspondence is observed between the taxonomy of parasites and their hosts and this has led to Fahrenholz's rule. This rule postulates that parasites and the hosts speciate in synchrony.
This leads to a prediction that phylogenetic trees of parasites and their hosts are topologically identical.
when the only events in the process of reciprocal natural selection in the host and parasite lineages were those of contemporaneous speciation in both the lineages then host and parasite phylogenies are fully congruent, hence supporting Fahrenholz'srule.
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Answer:
Cabbage juice
Explanation:
Red cabbage has pH indicator pigment. It changes color when mixed with acid or basic solution.
For acidic solution, the juice turns red.
For neutral, it shows purple color.
For basic solution have pH 8-9 : Blue
pH 10-11: Green
For strong basic solutions: yellow in color.
There are choices for this question namely:
<span>a. K+ leaks into cells.
b. Voltage-gated Na+ channels become inactivated.
c. Voltage-gated K+ channels become inactivated.
d. Na+ reaches equilibrium across the neural membrane and stops leaking in.
e. Voltage-gated Na+ channels close.
The correct answer is "voltage-gated Na+ channels become inactivated". In the events concerning an action potential, the first event is a stimulus that depolarize the resting membrane potential up to the threshold. When the threshold is reached there will be opening of voltage gated Na+ channels wherein sodium can enter the cell and make the membrane more positive therefore called depolarization. After depolarization, voltage gated Na+ channels become inactivated and K+ leaks out of the cell making the cell less negative hence repolarization. After which, more and more K+ ions leaks out making the membrane more negative than the resting membrane potential hence hyperpolarization. When K+ channels are inactivated, the cell membrane will eventually go back to its resting membrane potential.</span>
They would be the pistil, stamen, receptacle, and petal.
1. i
2.a
3.d
4.b
5.e
6.c
7.g
8.f
